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dimulka [17.4K]
3 years ago
12

Please write the equation and solve:

Mathematics
1 answer:
Olegator [25]3 years ago
3 0
A nonmember would have to go skating 11 times a year and a member would have to go skating 12 times a year.

They each paid $110. 

I hope this is correct!

Good luck:)

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Story problem to represent 3Divided by 1/2
Masja [62]
There were 3 pieces of pie and two kids wanted them. You gave each give one full piece of pie and then cut the last piece in half. After this, each kid had 1 1/2 pieces of pie. 
3 0
3 years ago
Which of the following functions is graphed below?
yanalaym [24]

Answer:

c) l x - 5 l - 4

Step-by-step explanation:

when you're graphing functions whatever is inside the paranthesis, square root or absolute value determines whether you go left or right, if its a negative you go to the right, if its positive you go to the left. So the opposite of what you would expect it to go

in this instance its - 5, so you go 5 units to the right

and the number outside determines if you go up or down, in this question its - 4 so you go down 4 units

7 0
2 years ago
10(8+3h) need help asap
LuckyWell [14K]

Answer:

80 + 30h

Step-by-step explanation:

10(8+3h)

Distribute

10*8 + 10*3h

80 + 30h

3 0
3 years ago
Read 2 more answers
Given that the product of two positive integers is 44, and their least common multiple is 22, what is their greatest common divi
swat32

Answer:

2

Step-by-step explanation:

For any positive numbers a,b we always have the following identity:

a\cdot b=gcd(a,b)\cdot lcm(a,b)

(gcd(a,b) denotes the greatest common divisor between a and b, and lcm(a,b) denotes the least common multiple between a and b)

In our case, we are given that a\cdot b = 44 and that lcm(a,b)=22. Plugging that in into our identity, we get:

44=gcd(a,b)\cdot 22

And so solving for gcd(a,b):

gcd(a,b)=\frac{44}{22}=2

5 0
3 years ago
Find the value or X. Round your answer to the nearest tenth.
RSB [31]

Answer:

x = 9.3

Step-by-step explanation:

tan 25° = x/20

0.4663 = x/20

x = 9.3

5 0
2 years ago
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