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Aleks [24]
3 years ago
6

Ray wants to buy an item worth $500. Which option is the most cost-effective?

Mathematics
2 answers:
LuckyWell [14K]3 years ago
5 0

Ray wants to buy an item worth 500$ in the most cost-effective way. Let's study each of the 3 cases and see with option is the best.

In the first option, he'll buy the item at list price with a coupon for $10 off. So he'll buy it at 500-10 =$490.

In the second option, he'll buy a membership for $35 and then get the item at a 15% discount. With a 15% discount, the price of the item will be 500 - (500*0.15) = 500 - 75 = $425. And with the membership price, he'll pay a total of 425 + 35 = $460.

The third option is to buy the item online at a 10% discount and pay $4 for the shipping. At 10% discount, the price of the item will be 500 - (500*0.1) = 500 - 50 = $450. And with cost of the shipping, he'll pay a total of 450+4 = $454.


So if he chooses the first option, he'll pay $490. With the second, he'll pay $460. And finally with the third, he'll pay $454.

So the third option is the most cost-effective, buying the item at $454.

Hope this helps! :)

-BARSIC- [3]3 years ago
5 0

Answer:

Buying the item online at a 10% discount and paying $4 extra for shipping

Step-by-step explanation:

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Answer:

   

Step-by-step explanation:

Let us denote probability of   spoilage as follows

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Both P ( T ∩ L ) .

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a )

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b )

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Probability of line spoilage given that there is transformer spoilage

P L/ T ) = P ( T ∩ L ) / P( T )

= .03 / .05

= 3 / 5 .

ii )

Probability of transformer spoilage but not line spoilage.

P( T ) - P ( T ∩ L )

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iii )Probability of transformer spoilage given that there is no line spoilage

[ P( T ) - P ( T ∩ L ) ] / 1 - P ( L )

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3 years ago
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For this question, set up an equation.  55% (or 0.55) times what number equals 22?

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Hope this helps!!

4 0
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