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Aleks [24]
3 years ago
6

Ray wants to buy an item worth $500. Which option is the most cost-effective?

Mathematics
2 answers:
LuckyWell [14K]3 years ago
5 0

Ray wants to buy an item worth 500$ in the most cost-effective way. Let's study each of the 3 cases and see with option is the best.

In the first option, he'll buy the item at list price with a coupon for $10 off. So he'll buy it at 500-10 =$490.

In the second option, he'll buy a membership for $35 and then get the item at a 15% discount. With a 15% discount, the price of the item will be 500 - (500*0.15) = 500 - 75 = $425. And with the membership price, he'll pay a total of 425 + 35 = $460.

The third option is to buy the item online at a 10% discount and pay $4 for the shipping. At 10% discount, the price of the item will be 500 - (500*0.1) = 500 - 50 = $450. And with cost of the shipping, he'll pay a total of 450+4 = $454.


So if he chooses the first option, he'll pay $490. With the second, he'll pay $460. And finally with the third, he'll pay $454.

So the third option is the most cost-effective, buying the item at $454.

Hope this helps! :)

-BARSIC- [3]3 years ago
5 0

Answer:

Buying the item online at a 10% discount and paying $4 extra for shipping

Step-by-step explanation:

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How much will a person pay for 1.1 pounds of bananas at a price of ​$1.86 per​ pound?
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2 years ago
Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa
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Using the z-distribution, it is found that since the <u>test statistic is greater than the critical value</u>, it can be concluded that the mean length of jail time has increased.

At the null hypothesis, it is <u>tested if the mean length of jail time is still of 2.5 years</u>, that is:

H_0: \mu = 2.5

At the alternative hypothesis, it is <u>tested if it has increased</u>, that is:

H_1: \mu > 2.5

We have the <u>standard deviation for the population</u>, thus, the z-distribution is used. The test statistic is given by:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • \sigma is the standard deviation of the sample.
  • n is the sample size.

For this problem, the values of the <u>parameters</u> are: \overline{x} = 3, \mu = 2.5, \sigma = 1.5, n = 26

Hence, the value of the <u>test statistic</u> is:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{3 - 2.5}{\frac{1.5}{\sqrt{26}}}

z = 1.7

The critical value for a <u>right-tailed test</u>, as we are testing if the mean is greater than a value, with a <u>significance level of 0.05</u>, is of z^{\ast} = 1.645

Since the <u>test statistic is greater than the critical value</u>, it can be concluded that the mean length of jail time has increased.

A similar problem is given at brainly.com/question/24166849

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2 years ago
Please help me match this
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4/5=0.8
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3/8=0.375
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You could have use a calculator for this but you’re welcome
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