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3 years ago

Ray wants to buy an item worth $500. Which option is the most cost-effective?

2 answers:

5 0

Ray wants to buy an item worth 500$ in the most cost-effective way. Let's study each of the 3 cases and see with option is the best.

In the first option, he'll buy the item at list price with a coupon for $10 off. So he'll buy it at 500-10 =$490.

In the second option, he'll buy a membership for $35 and then get the item at a 15% discount. With a 15% discount, the price of the item will be 500 - (500*0.15) = 500 - 75 = $425. And with the membership price, he'll pay a total of 425 + 35 = $460.

The third option is to buy the item online at a 10% discount and pay $4 for the shipping. At 10% discount, the price of the item will be 500 - (500*0.1) = 500 - 50 = $450. And with cost of the shipping, he'll pay a total of 450+4 = $454.

So if he chooses the first option, he'll pay $490. With the second, he'll pay $460. And finally with the third, he'll pay $454.

So the third option is the most cost-effective, buying the item at $454.

Hope this helps! :)

-BARSIC- [3]3 years ago

5 0

Answer:

Buying the item online at a 10% discount and paying $4 extra for shipping

Step-by-step explanation:

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r = 2,85 feet

h = 8,56 feet

Step-by-step explanation:

Area of two circular caps (m ^(2)) : 2* pi* r^(2) (where r is the radius of circular cap) Area of wall (m ^(2)) is 2*pi*r*h (where h is the height of drum)

V= pi*r^(2)*h so h=V/pi*r^(2) (1)

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Cost of (both top and bottom cap) = 2*40,97*pi* r^(2) so:

C(caps) = 257,29* r^(2) $/squaer feet

Total cost of cylnder = cost of wall + cost of caps

Total cost f cylinder: F(c)= 55*pi*r*h+257,29* r^(2)

F(c) = 172,7*r*h + 257,29*r^(2) F(c) is F(r)

Since from (1) we have h=218,276/pi*r^(2)

F(r) = (172,7)*r*(69,514)/r^(2) +257,29*r^(2) F(c) = 12005/r + 257,29*r^(2)

Taken the first dervative

F´(r)= -12005*(1)/r^(2) +2*257,29*r F´(r) = -12005*(1)/r^(2) +514,58*r

f F´(r) = 0 -12005*(1)/r^(2) + 514,58*r =0

-120005 + 514,58*^(3) = 0 514,58*^(3) = 12005 r =cubic root (23,32)

r = 2,85 ft

if we replace this value en F(r) we can see F(r) tend to infinite both when r tend to 0 and when r tends to infnite so there is a minimun for the functon

r = 2,85 ft and h = 8,56 ft

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