AB = BC, so 3x-2 = 2x+4. Also, BC = CA, so 2x+4=x+10.
Solve this system of linear equations:
3x-2 = 2x+4
2x+4=x+10 => x=6
Check: Does AB=BC? Does AB=BC?
Does 3(6)-2 = 2(6)+4? Does 16=16? YES.
Does BC = CA? Does 2(6)+4 = 6+10? YES
x = 6 (answer)
One revolution also corresponds to an angular displacement of 2π rad.
So, the angular velocity is
120 rev/min = (120 rev/min) * (2π rad/rev) = 240π rad/min
The answer to the question
check the picture below.
so the triangular prism is really just 3 rectangles and 2 right-triangles,
now, we know the base of one of the triangles is 2.6, what's its height?
since it's a right-triangle, we can simply use the pythagorean theorem to get "h".

so, we can now, simply get the area of both of the triangles and the three rectangles and sum them up, and that's the area of the triangular prism.
![\bf \stackrel{two~triangles}{2\left[ \cfrac{1}{2}(2.6)(4.5) \right]}~~+~~\stackrel{rectangle}{(2.6\cdot 4.3)}~~+~~\stackrel{rectangle}{(4.3\cdot 3.9)}~~+~~\stackrel{rectangle}{(4.3\cdot 5.2)} \\\\\\ 11.7+11.18+22.36\implies \blacktriangleright 45.24 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Btwo~triangles%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%282.6%29%284.5%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7Brectangle%7D%7B%282.6%5Ccdot%204.3%29%7D~~%2B~~%5Cstackrel%7Brectangle%7D%7B%284.3%5Ccdot%203.9%29%7D~~%2B~~%5Cstackrel%7Brectangle%7D%7B%284.3%5Ccdot%205.2%29%7D%0A%5C%5C%5C%5C%5C%5C%0A11.7%2B11.18%2B22.36%5Cimplies%20%5Cblacktriangleright%2045.24%20%5Cblacktriangleleft)
They all add 3 then subtract it by 4