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diamong [38]
3 years ago
15

Which series of transformations maps △ABC to △A′B′C′?

Mathematics
2 answers:
denis-greek [22]3 years ago
5 0

Answer:

A

Step-by-step explanation:

If you translate left one unit, then reflect across the x axis, you get the ending figure

Alik [6]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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2 years ago
(a + b)(a 2 - ab + b 2)
JulsSmile [24]

Answer:

a³ + b³

Step-by-step explanation:

Given

(a + b)(a² - ab + b²)

Each term in the second factor is multiplied by each term in the first factor, that is

a(a² - ab + b²) + b(a² - ab + b²) ← distribute both parenthesis

= a³ - a²b + ab² + a²b - ab² + b³ ← collect like terms

= a³ + b³

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Read 2 more answers
The volume formula for a right pyramid is V=
morpeh [17]

Answer:

A.Area of the base

Step-by-step explanation:

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4 0
3 years ago
Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)
lisov135 [29]

Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

Step-by-step explanation:

(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

Multiply 2x-3y=3 by 2:

\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}

Subtract the equations

4x-6y=3\\-\\4x-6y=6\\------\\0=-3

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

Isolate x for 4x-6y=10

x=\frac{5+3y}{2}

Substitute x=\frac{5+3y}{2} into the second equation

16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40

The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

3 0
3 years ago
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