Choose the correct zeros for the following quadratic function

A shelf has different sizes of bottles of laundry detergent. This line plot shows the number of cups of laundry detergent in eac

salantis [7]

Answer:

2 / 3 loads

Step-by-step explanation:

From. The plot, we can conclude that, the detergent that has the most bottles is that with 5 ; the number of cups in the detergent with 5 bottles is 12 cups

Number of cups used for each load of laundry = 18 cups

The loads of laundry Eric can do is thus :

Number of cups of detergent / number of cups used for each load of laundry

= 12 / 18

= 2 / 3 loads

8 0

3 years ago

Express the following numbers in standard form. [A] 509.78 [B] 0.0289 Can someone please help me ? I need to answer that questio

STALIN [3.7K]

Answer:

(A) 509.78

We need to move the decimal point after the first non-zero digit

So,

=> 5.0978 × 10² (Since the decimal point is moved two places to the left)

(B) 0.0289

Again after the first non-zero digit:

So, it becomes:

=> 2.89 × 10⁻² (Since the decimal point is moved 2 places to the right so it will be negative also)

8 0

3 years ago

Read 2 more answers

Review

Doss [256]

The answer is bbc or if that’s not the answer the then it’s bbl THANK ME LATERRRR

5 0

2 years ago

On a science exam, Jackson scored 85 out of 100 possible points. There were 20 questions on the exam. Each question was worth th

d1i1m1o1n [39]

Do 85÷20 and then add it to 100

4 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$