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weeeeeb [17]
3 years ago
15

The fairy tale spectacular is coming to town. Admission to the fair costs $42.50 and each ride costs $.65. You have $60 to spend

at the fairy tale spectacular including admission.
Part A: write an inequality that represents this situation.
Part B: solve the inequality to determine the maximum number of rides you can enjoy at the fairy tale spectacular.
Mathematics
1 answer:
galina1969 [7]3 years ago
7 0

Part A: 42.50+0.65x<60

Part B: You can enjoy maximum 26 rides at the fairy tale spectacular.

Step-by-step explanation:

Given,

Admission cost to fair = $42.50

Cost of each ride = $0.65

Amount you can spend = $60

Let,

x be the number of rides you can take.

Admission fair + Cost of each ride*number of rides < Amount you can spend

Part A: write an inequality that represents this situation.

42.50+0.65x<60

Part B: solve the inequality to determine the maximum number of rides you can enjoy at the fairy tale spectacular.

42.50+0.65x

Dividing both sides by 0.65

\frac{0.65x}{0.65}

Rounding off to nearest whole number;

x<27

Less than 27 means, you cannot take 27 rides, therefore,

You can enjoy maximum 26 rides at the fairy tale spectacular.

Keywords: inequality, division

Learn more about inequalities at:

  • brainly.com/question/10629017
  • brainly.com/question/10633485

#LearnwithBrainly

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Answer:

2/5, 0.4, 40%

7/10, 0.7, 70%

1/2, 0.5, 50%

1/2, 0.5, 50%

4/5, 0.8, 80%

3/5, 0.6, 60%

3/10, 0.3 ; 30%

Step-by-step explanation:

Sample space = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10)

P(less Than 5) :

Required = (1, 2, 3, 4) = 4 observations

P(less than 5) = 4 / 10 = 2 / 5 = 0.4 = 40%

Greater than 3) = (4, 5,6,7,8,9,10) = 7 observations

P greater Than 3) = 7/10 = 0.7 = 70%

Odd = (1,3,5,7,9) = 5

P(odd) = 5 / 10 = 1/2 = 0.5 = 50%

(even) = (2,4,6,8,10) = 5

P(even) = 5 / 10 = 1/2 = 0.5 = 50%

Not a multiple of 4 = (1,2, 3,5,6,7,9,10) = 8

P(not A multiple of 4) = 8/10 = 4/5 = 0.8 = 80%

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4 0
2 years ago
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Answer:

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Step-by-step explanation:

$1.85 for a sandwich

$1.15 for a drink

$0.65 for a bag of chips

$1.10 for two apples.

The total amount of money the student spent at lunch, in dollars and cents is:

$1.85 + $1.15 + $0.65 + $1.10

= $4.75

In words = 4 dollars and 75 cents

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<u>Given</u>:

The given function f(x)=19,000 \cdot 0.96 ^x which models the value of Mark’s car, where x represents the number of years since he purchased the car.

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