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alexandr1967 [171]
3 years ago
11

On a coordinate plane, the vertices of a rectangle are (-2,1), (3,1), (-1,-4), and (3,-4). what is the perimeter of the rectangl

e?
Mathematics
1 answer:
Ratling [72]3 years ago
4 0
You can graph the points, then use the distance formula to find each side length. Then just add the sides together.
Distance formula:
d =  \sqrt{(x_2-x_1)^{2} + (y_2-y_1)^2 }
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22.5 + 7(n−3.4) simplified
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Which statement is not true about the patter shown?
brilliants [131]

Answer:

Each fraction is greater than the previous fraction.

Step-by-step explanation:

Every statement is true except, the one that says "Each fracton is greater than the previous fraction." This statement is not true. I know it looks like it, but let's think about it. Each fraction is equivalent to 2/3, which means they are technically equal to each other. So that means that each fraction is not greater than the previous one. This means that the statement "Each fraction is equal to the previous fraction in the pattern multiplied by 2/2" is a true statement.

2/3 x 2/2 = 4/6

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8/12 x 2/2 = 16/24

16/24 x 2/2 = 32/48

So that means that the next fraction in the pattern is indeed 32/48, making the last statement true.

3 0
3 years ago
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
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Natalka [10]
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3 years ago
What information does the ordered pair (3, 87) represent?
mafiozo [28]

<span>The 3 (x-coordinate) indicates that from the origin (0,0) in the cartesian plane, you have traveled four units to the right along the x-axis(the horizontal axis). </span>

<span>The 87 indicates that you traveled 87 units up in the y-axis(vertical axis), in line with the point 3 in the x-axis.This number is the y-coordinate, the second number in the ordered pair. </span>

8 0
3 years ago
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