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Hunter-Best [27]
3 years ago
8

Im desperate for help please

Mathematics
2 answers:
netineya [11]3 years ago
7 0
Answer for this question is :

A
Andrew [12]3 years ago
6 0

Answer:

A

Step-by-step explanation:

THISS IS SO EASY! THE DIVINED

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The variable q represents a positive integer. Does 3(59 + 9) + 5q represent a number that is greater than, less than, or equal t
hjlf

Answer:

Depends on the value of q.

Step-by-step explanation:

3(59+9) + 5q = 3(68) + 5q = 204 + 5q

4(59+6) = 260

7 0
3 years ago
The expression square root 300 is equivalent to... <br><br> PLEASE BRAKE DOWN!!
klio [65]
Um kind of confused what you're asking but, the square root of 300 is 90,000.

As far as breaking it down, it's basically what is 300 x 300.

aka

300^2
4 0
3 years ago
Indicate the equation of the line meeting the given conditions. Please put the equation in standard form. Containing A(1, 3) and
Sergio [31]
M = y2-y1/x2-x1
    = 2 - 3 / 0 - 1
    = -1 / -1
    = 1

Y = x + b
2 = 0 + b
2 = b

Y = x + 2
0 = x - y + 2
-2 = x - y
2 = -x + y

Therefore, the equation of the line in standard form is 2 = -x + y

(not sure if done right lol)
6 0
4 years ago
Read 2 more answers
An internal study by the Technology Services department at Lahey Electronics revealed company employees receive an average of 4.
Leno4ka [110]

Answer:

P(4 non-work-related e-mails)=0.1933

P(7 or more non-work-related e-mails)=0.1442

P(3 or less non-work-related e-mails)=0.3771

Step-by-step explanation:

A Poisson distribution is useful to measure the probability of a number of events in a given period, in this problem, receiving a non-work-related e-mail would be the event and an hour would be the period of time.

Its probability mass function is f(k; \lambda) = P(x=k) = \frac{\lambda^k e^{-\lambda}}{k!}, being k the number of events and  λ how many sucesses (events) are per period of time (4.3 in this case)

First, we calculate what is the probability of receiving exactly 4 e-mails:

f(k; \lambda) =P(k=4) =\frac{4.3^4 e^{-\4.3}}{4!}=0.1933

As k is a discrete variable, to know the joint probability of different number of events we add the probability of each value.

The probability of receiving 7 or more is the sum of P(7), P(8), ..., P(∞):

P(k\geq 7 ) =\sum_{i=7}^{\infty}\frac{4.3^i e^{-\4.3}}{i!}=0.1442

Last, the probability of receiving 3 or less is the sum of P(0), P(1), P(2) and P(3):

P(k\leq3 ) =\sum_{i=0}^{3}\frac{4.3^i e^{-\4.3}}{i!}=0.3771

3 0
3 years ago
Complete the proof in picture
BARSIC [14]

it won't let me type the answer I may be missing something but it says I am using rude words so sorry if I am

5 0
3 years ago
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