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satela [25.4K]
3 years ago
14

Adding to "undo" subtraction and subtracting to "undo" addition are both examples of using inverse operations to solve equations

. Think of another pair of inverse operations in mathematics. How do these inverse operations "undo" each other?
Mathematics
1 answer:
Andrews [41]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

Multiplication and division are also inverse operations

15 * 10 = 150

150 ÷10 = 15

Divide 150 by 10 and we get 15 back

The division undoes the multiplication

This also works in reverse

150 ÷ 10 = 15

15*10 =150

The multiplication undoes the division

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Oduvanchick [21]

Answer:

4y+7

Step-by-step explanation:

there is no way of knowing what y is

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What is 9.33 as a fraction in simplest form
netineya [11]
9 33/100 is the answer
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The admission fee is $1.50 for children and $4.00 for adults. If 2700 people enter and $7800 is collected how many children and
Snowcat [4.5K]

Answer:

1200 children and 1500 Adults

Step-by-step explanation:

Suppose x be the children and y be the adults as total people are 2700 that have entered so we can write an equation as  

x+y=2700    (Equation 1)

and as per child $1.50 is the cost and $4 for every adult and collectively we have got $7800 so we can write the equation as  

1.50x+4y=7800 (Equation 2)

Extracting the value of y from equation 1

Y=2700-x (Equation 3)

Putting the value of y from equation 3 into equation 2

1.50x+4(2700-x)=7800

1.50x+10800-4x=7800

1.50x-4x=7800-10800

-2.5x=-3000

Cancellation of negative signs on both sides

x=3000/2.5

x=1200

Putting the value of x in equation 3 to get the value of y

y=2700-1200

y=1500

5 0
3 years ago
PLEASEEEE HELP ME WITH THIS ALGEBRA 1
AleksandrR [38]

Answer:

Step-by-step explanation:

total cost = tickets( c) +50

1400 = 4 (c) + 50

1350 = 4 (c)

337.50 = c

5 0
3 years ago
A hunter is at a point on a riverbank. He wants to get to his cabin located 2 Miles North and 8 Miles West. He can travel 5 Mph
miskamm [114]

Answer:

Option A

Step-by-step explanation:

A hunter travels to his cabinet located at 2 Miles North and 8 Miles West.

Let "d" be the distance traveled before reaching the rocky ground at point say "P". Let the cabin be at "C"

The distance between C and P is given by

\sqrt{(2^2+(8-d)^2}\\

Let "t" be the time taken to travel distance CP.

T = \frac{d}{5} + \frac{\sqrt{2^2+(8-d)^2} }{3}

Minimum time will be when "t" is equal to zero

Differentiating the above equation wrt "d", we get -

= \frac{1}{5} + \frac{1}{3} (\frac{-2(8-d)}{2\sqrt{2^2+(8-d)^2} } )= 0\\\frac{1}{5} = \frac{1}{3} \frac{(8-d)}{\sqrt{4+(8-d)^2} } \\3\sqrt{4+64+d^2-16d} = 40-5d\\

On squaring both the sides , we get -

3\sqrt{4+64+d^2-16d} = 40-5d\\9(68+d^2-16d)= 1600+25d^2 -400d\\612+9d^2-144d=1600+25d^2 -400d\\16d^2-256d+988=0\\d_1 = 9.5\\d_2 = 6.5

"d" cannot be greater than 8 miles.

Hence, the value of "d" is equal to 6.5

Option A

8 0
3 years ago
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