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satela [25.4K]
3 years ago
14

Adding to "undo" subtraction and subtracting to "undo" addition are both examples of using inverse operations to solve equations

. Think of another pair of inverse operations in mathematics. How do these inverse operations "undo" each other?
Mathematics
1 answer:
Andrews [41]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

Multiplication and division are also inverse operations

15 * 10 = 150

150 ÷10 = 15

Divide 150 by 10 and we get 15 back

The division undoes the multiplication

This also works in reverse

150 ÷ 10 = 15

15*10 =150

The multiplication undoes the division

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5 feet<br> 4 feet<br> What is the perimeter?<br> 16 feet<br> 14 feet<br> 18 feet
brilliants [131]

perimiter means all the way around, and im assuming this is a 4-sided shape, so 5+5+4+4 = 18 ft.

8 0
3 years ago
Tim is playing a game. His score in round 1 is 1.7 points, in round 2 is 5.1 points, in round 3 is 15.3 points, and it continues
tatiyna

The recursive definition for the geometric sequence is given as follows:

a_n = 3a_{n-1}, a_1 = 1.7

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

The recursive definition of a geometric sequence is given by:

a_n = qa_{n-1}

In this problem, we have that the first term and the common ratio are given, respectively, by:

a_1 = 1.7, q = \frac{15.3}{5.1} = \frac{5.1}{1.7} = 3.

Hence the recursive definition is given by:

a_n = 3a_{n-1}, a_1 = 1.7

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

4 0
2 years ago
Solving linear-quadratic systems algebraically<br><br> y+2=(x-3)^2<br> y+3=x
Vikentia [17]

Answer:

(2, - 1 ) and (5, 2 )

Step-by-step explanation:

y + 2 = (x - 3)² → (1)

y + 3 = x ( subtract 3 from both sides )

y = x - 3 → (2)

Substitute y = x - 3 into (1)

x - 3 + 2 = (x - 3)² ← expand using FOIL

x - 1 = x² - 6x + 9 ( subtract x - 1 from both sides )

0 = x² - 7x + 10 ← in standard form

0 = (x - 2)(x - 5) ← in factored form

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x - 5 = 0 ⇒ x = 5

Substitute these values into (2) for corresponding values of y

x = 2 : y = 2 - 3 = - 1 ⇒ (2, - 1 )

x = 5 : y = 5 - 3 = 2 ⇒ (5, 2 )

5 0
3 years ago
Solve this equation for x. Round your answer to<br> the nearest hundredth.<br> 3 = In(x + 9)
Mrac [35]

Answer:

x ≈ 11.09

Step-by-step explanation:

Using the rule of logarithms

log_{b} x = n ⇒ x = b^{n}

Given

ln(x + 9) = 3 , that is

log_{e} (x + 9) = 3 , then

x + 9 = e³ ( subtract 9 from both sides )

x = e³ - 9 ≈ 11.09 ( to the nearest hundredth )

7 0
3 years ago
Please answer this question and I will give you brainliest !! Show your work !!
Diano4ka-milaya [45]

Answer:

Initiation fee:

$400

Monthly fee:

$10

Step-by-step explanation:

First, let's start by calculating the monthly fee.

Over a period of 5 months (5 -> 10 months), the member paid 50 dollars more.  We can divide this number by 5 to find the monthly fee. The monthly fee is $10.

Now, we can find the initiation fee. After 5 months with the gym, the member had spent $450. As we already know, $50 is the price for 5 months, so the member paid $50 in monthly fees.

We subtract $50 from the total cost ($450) to find that the initiation fee is $400.

Now, we can write the equations for each statement.

<em>Let m represent the monthly fee and i represent the initiation fee:</em>

"At the end of 5 months, a member had paid a total of $450"

5m + i = 450

"At the end of 10 months, she had paid a total of $500.

You could use 2 equations for this statement:

10m + i = 500

OR, if you use the above facts to calculate the fact that there was a $50 increase from those five months, and exclude the initiation fee and the previous five months:

5m = 50

Hope this helps!

4 0
3 years ago
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