Answer:
0.630
Step-by-step explanation:
Simply evaluating, we get v (0) = 1, v (0.31831) = 0.630, v (2) = 1.566. Thus, the minimum velocity over the interval [ 0, 2] is 0.630.
foot marker 320 at t=0
8 sec x 85 ft/s =680 ft
1,000ft - 680 ft = 320 ft
Answer: ( − 2) ( + 9)
