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Taya2010 [7]
3 years ago
11

a steel ball has a diameter of 1.6 centimeters what is the volume of this steel ball round your anwser to the nearest tenth if n

ecessary (AHHH HELP ME PLEASE)

Mathematics
1 answer:
emmasim [6.3K]3 years ago
8 0
Volume of a sphere is 4/3 x pi x r(cubed)— so based on that I think it’s 2.14 cm cubed

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Help me please and thanks you:)
aniked [119]
This answer is 6x .... 
8 0
3 years ago
The frequency table shows the scores from rolling a dice<br><br> work out the mean
umka2103 [35]
You have to add all of your frequency’s together and divide by 6 for the 6 scores. your mean would be 2
6 0
3 years ago
What is the smallest value of n such that an algorithm whose running time is 100n 2 runs faster than an algorithm whose running
Semmy [17]

Answer:

n = 15

Step-by-step explanation:

For inputs of the value of n, the running time for the algorithm A is 100n^2 and that of B is 2^n.

If A is to run faster than B, 100n^2 must be smaller than 2^n.

Let's check from n = 1 to know the value of n that fits

n = 1

100(1)^2 > 2^1

100 > 2

n = 2

100(2)^2 > 2^2

400 > 4

n = 4

100(4)^2 > 2^4

1600 > 16

n = 8

100(8)^2 > 2^8

6400 > 2^8

n = 16

100(16)^2 < 2^16

25600 < 2^16

This implies that between n = 8 and 16, A starts to run faster than B

n = (8+16)/2 = 12

100(12)^2 > 2^12

14400 > 2^12

n = (12+16)/2 = 14

100(14)^2 > 2^14

19600 > 2^14

n = (14+16)/2

n = 15

100(15)^2 < 2^15

22500 < 2^15

At n= 15, A starts running faster than B

8 0
3 years ago
Write an equation and solve:
dalvyx [7]

Answer:

11 weeks

Step-by-step explanation:

34+10x=144 equation

10x=110

x=11

check answer

11*$10=$110 money after 11 weeks at $10/week

    +.       34 money saved

     =.     144 money needed.

8 0
3 years ago
Solve.<br> −8.5d ≥ 20<br><br> d ≤ –170<br> d ≥ –170
saw5 [17]

Answer:

\rm =>D \leqslant 2.352941

Step-by-step explanation:

−8.5d ≥ 20

Divide both sides by -8.5:

=> \cfrac {- 8.5 \: d}{  - 8.5} \ \geqslant  \cfrac{20}{ - 8.5}

\rm=>d \leqslant 2.352941

This is the answer.

3 0
2 years ago
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