Cosecθ=sq.rt of 65/8. hope it will help you
Answer:
is this your only question?
Answer:
24s^2, 54s^2, 96s^2
Step-by-step explanation:
Let s represent the initial side length of the cube. Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).
a) Now suppose we double the side length. The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),
b) tripled: A = 6(3s)^2 = 54x^2
c) quadrupled? A = 6(4s)^2 = 96s^2
Answer:
(5.4k+7.9m+8.1n) centimeters
Step-by-step explanation:
Given the side length of a triangle;
S1 = (1.3k+3.5m) cm
S2 = (4.1k-1.6n) cm
S3 = (9.7n+4.4m) cm
Perimeter of the triangle = S1+S2 + S3
Perimeter of the triangle = (1.3k+3.5m) + (4.1k-1.6n) + (9.7n+4.4m)
Collect the like terms;
Perimeter of the triangle = 1.3k+4.1k+3.5m+4.4m-1.6n+9.7n
Perimeter of the triangle = 5.4k+7.9m+8.1n
Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters
