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scoundrel [369]
4 years ago
8

What is the median?

Mathematics
2 answers:
expeople1 [14]4 years ago
4 0
75, 76, 80, 83, 84, 85, 89, 91, 94, 94

The median is 84.5
You add the two middle numbers (84, 85) and divide by 2.
faltersainse [42]4 years ago
4 0
The answer is 84. You have to put it in least to greatest. Then find the middle number.
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How To Solve The Equation 3(x-6)=10x+3 ?
kykrilka [37]
<span><u>3(x-6)=10x+3</u></span>

Expand the left side:

3x-18 = 10x + 3

Subtract 3x from each side:

-18 = 7x + 3

Subtract 3 from each side:

-21 = 7x

Divide each side by 7 :

<u>-3 = x</u>

4 0
3 years ago
Read 2 more answers
The volume of a box for earrings is 216 cubic centimeters. What is the length of one edge of the box plz help it's due tm
Murrr4er [49]
I’m pretty positive you divide 216 by 4, since that’s the amount of sides a box normally has. The answer would be 54 cubic centimeters. Please let me know if I’m correct, hopefully this helped.
4 0
3 years ago
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Inveres laplace transform (3s-14)/s^2-4s+8​
Olenka [21]

Complete the square in the denominator.

s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4

Rewrite the given transform as

\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}

Now take the inverse transform:

L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}

5 0
3 years ago
Which king of function best models the date in the table
attashe74 [19]
We can see that the y-intercept (the value of y when x=0) is -1 by looking at the table.

Now we just need the slope, or "m" of the linear equation.

m=(y2-y1)/(x2-x1)  in this case:

m=(-2--1)/(1-0)

m=-1/1

m=-1

Now that we know m and b of y=mx+b we can say the line is:

y=-x-1

So this is a linear equation, y=-x-1
6 0
4 years ago
In the adjoining figure, area of trangle ABC is
Zepler [3.9K]

Answer:

PQ=4\ cm

Step-by-step explanation:

see the attached figure with the letter D to better understand the problem

we know that

The segment side AD is the height of triangle ABC

so

Triangles PBQ and ABD are similar by AA Similarity Theorem

The area of triangle ABC is equal to

A=\frac{1}{2}(BC)(AD)

we have

A=48\ cm^2\\BC=12\ cm

substitute

48=\frac{1}{2}(12)(AD)

AD=8\ cm

Remember that

If two triangles are similar  then the ratio of its corresponding sides is proportional

so

\frac{BP}{AB}=\frac{PQ}{AD}

substitute the given values

\frac{BP}{2BP}=\frac{PQ}{8}

\frac{1}{2}=\frac{PQ}{8}

PQ=4\ cm

3 0
3 years ago
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