$\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2,\ \text{then}\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\\text{Convert the equation to the slope-intercept form}\ y=mx+b.\\\\5x-8y=8\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\-8y=-5x+8\qquad\text{divide both sides by (-8)}\\\\y=\dfrac{5}{8}x-1\to m_1=\dfrac{5}{8}\\\\perpendicular:\ m_2=-\dfrac{1}{\frac{5}{8}}=-\dfrac{8}{5}\\\\parallel:\ m_2=\dfrac{5}{8}$

8 0

3 years ago

What’s the domain of the function above?

Lelechka [254]

2 is the answer to your question

8 0

3 years ago

X + y = 3

hoa [83]

Answer: x=2
step by step explanation:

6 0

3 years ago

Read 2 more answers

Please help me please !

Morgarella [4.7K]

Hi there!

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I believe your answer is:

Option C

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Here’s why:

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$\text{\underline{The Slope Formula Is:}}\\\\m=\frac{y_2-y_1}{x_2-x_1}\\\\(x_1,y_1)\text{ and } (x_2,y_2)\text{ are two points given.}\\\\\text{We are given the points: } (3,5) \text{ and } (9,2).\\\\\text{\underline{The formula for the points should be:}}\\\\m=\frac{5-2}{3-9}, \text{where } (9,2) \text{ is }(x_1,y_1)\text{ and } (3,5) \text{ is } (x_2,y_2).$

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Hope this helps you. I apologize if it’s incorrect.

7 0

3 years ago