Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
See https://web2.0calc.com/questions/help-please_82538.
x = 58°
<u>Explanation:</u>
According to the diagram, lines HI and JK are parallel to each other.
∠AHI = 60°
∠JKI = 62°
∠JKI and ∠HIA are equal because when two lines are parallel then the corresponding angles are equal.
So,
∠JKI = ∠HIA = 62°
In ΔHIA,
∠AHI + ∠HIA + ∠IAH = 180°
60° + 62°+ x = 180°
122° + x = 180°
x = 180° - 122°
x = 58°
14/8 = 1.75
The scale factor is 1.75 because 8* 1.75 = 14
