The answer to this is - 23/20
-(2x - 8) = 4
-2x + 8 = 4
-2x = 4 - 8
-2x = -4
x = -4/-2
x = 2
Answer:
a.
b. The fret should be placed 25 cm far from the bridge.
c. So, the fraction of string at which the fret is placed is .
Step-by-step explanation:
We are given,
The function representing the distance of a fret from the bridge by ,
where r = length of the root note string and n = number of notes higher than root note.
Now, Louis want to produce notes on a 50 com string. This gives r = 50.
Thus, .
1. It is required to produce notes which are 1 octave ( 12 notes ) higher than the root note. This gives that n = 12.
So, we get, r = 50 and n = 12 which gives us the function as,
a.
i.e.
i.e.
i.e.
b. Thus, the fret should be placed 25 cm far from the bridge.
Now, as the fret is placed 25 cm far on the string having length 50 cm.
c. So, the fraction of string at which the fret is placed is i.e. .
Answer:
$962.00
Step-by-step explanation:
We can start from the first sentence of the word problem and work from there.
First, the employee is working for 40 hours at $18.50 per hour. This means that for each hour, the employee is gaining $18.50 . This can be represented as $18.50 * 40 = $740 for their base pay.
Next, the employee works 8 hours of overtime at 1.5 * base pay (18.50). For each hour of overtime they work, they earn 1.5 * 18.50 = $27.75 dollars. Their earnings from overtime work for the week can be represented as
8 * 27.75 = $222
Because all the employee's hours are encompassed in overtime and base pay, we can add the two together to get
740 + 222 = $962.00 for their total pay for the week
The anwser is zero
You see, 5 to the exponent of 0 is 5 0 times then if you multiply 5 to the explnent of 1 by zero the anwser is zero because zero times 5 is zero