the length of the side of this square is 
cm
Answer:
Solutions Given:
let diagonal of square be AC: 8 cm
let each side be a.
As diagonal bisect square.
let it forms right angled triangle ABC .
Where diagonal AC is hypotenuse and a is their opposite side and base.
By using Pythagoras law
hypotenuse ²=opposite side²+base side²
8²=a²+a²
64=2a²
a²=
a²=32
doing square root on both side
a=±
a=±2*2
Since side of square is always positive so
a=4 or 5.65 cm
Answer:
L = 7 W= 12
Step-by-step explanation:
Ok so we already know that a rectangle is not even so the numbers will have to be 2 diff numbers.
The length is 5 feet less then width
w*l= 84
1* 84 2* 41 3*28 4*21 6*14 7*12
84-1 41-2 28-3 21-4 14-6 12-7
83 39 25 19 8 5
So,
your equation would be l*w = 7*12
Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector
Answer:
x = 45, y = 5
Step-by-step explanation:
It is given that two lines form a linear pair with equal measures. Therefore, the angle between the two lines will be 90. Now, according to the question,
2x + 20y - 10 =90
2x+20y = 100
x + 10y = 50
And
2x = 20y-10
x = 10y -5
x - 10 y = -5
Now, adding x + 10y = 50 and x - 10y =-5, the value of x can be found. The required value will be:
x + 10y =50
x - 10y = -5
------------------
x = 45
Therefore, the value of y after substitution of the value of x in one of the equations will be:
90 = 20y - 10
20 y = 100
y = 5
Hence, the required value of x and y are 45 and 5 respectively.
