Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,
Hence, this is the required solution.
Answer:
I think they are independent
Step-by-step explanation:
Answer:
1) x=10
2) x=6
3) x=13
Step-by-step explanation:
1) 15x-17+4x+7=180
19x-10=180
19x=190
x=10
2) 13x+5=16x-13
5+13=16x-13x
18=3x
x=6
3) 9x+7=11x-19
7+19=11x-9x
26=2x
x=13
Answer:
the width=15; the length=20
Step-by-step explanation:
1. to solve the given equation: x²+5x-300=0;
x₁= -20; x₂=15, where 'x' can be only positive value. It means x=15;
2. according to the condtition the length is more, it means 15+5=20.
3. the width is x=15; the length is 20.
I believe it would be 3×4x<35
