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V125BC [204]
3 years ago
14

Find the value of d, the length of the diagonal across the square. If necessary,

Mathematics
1 answer:
icang [17]3 years ago
3 0

Answer:

Step-by-step explanation:

Use Pythagorean theorem,

d² = 4² + 4²

   = 16 + 16

d² = 32

d = √32

d = 5.67 units

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4 years ago
Evaluate the expression 3d if d =5
Vinvika [58]

Answer:

15

Step-by-step explanation:

since 3d is multiplying, it would be set up as 3*5=15

3 0
3 years ago
Read 2 more answers
In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.
vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

<u>Solution:</u>

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>

\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100

\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}

<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>

\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

7 0
3 years ago
Tell whether -2 is a solution of the inequality n-5&lt;8
ruslelena [56]

Answer:

-2 is a solution

Step-by-step explanation:

-2-5<8

-7<8

6 0
3 years ago
Please answer as many as you can from problems 2-8
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8. 1- 1/b+2
H0P3 It H3LPS :)
#Itwashardwork

3 0
3 years ago
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