Answer:
The different magnetic shielding effects of the carbonyl double bond in CH0, the CH₂ (a) and CH₂ (b) protons show different chemical shifts
Because the degree of shielding depends on electron density round the proton, the neighboring carbonyl group will increase this density in geranial form.
Now in CH₂ the electron density is increased around CH₂ (a) protons in neral form due to the carbonyl group, and thus it has a lower z values than the corresponding geranial form.
In the case of CH₃ (b) protons. thus they have lower z values and higher chemical shift than the corresponding nera form.
Explanation:
Solution
Due to the different magnetic shielding effects of the carbonyl double bond in CH0, the CH₂ (a) and CH₂ (b) protons show different chemical shifts.
Since the degree of shielding depends on electron density round the proton, the neighboring carbonyl group will increase this density in geranial form more in case of CH₃ (b) protons. thus they have lower z values and higher chemical shift than the equivalent nera form.
Similarly, the electron density is increased around CH₂ (a) protons in neral form due to the carbonyl group, and thus it has a lower z values than the equivalent geranial form.
Explanation:
Sulfide anion is depicted by S²⁻
Sulfur is an element with atomic number of 16;
In an atom;
there are subatomic particles:
Protons are the positively charged particles
Electrons are negatively charged
Neutrons do not carry any charges.
In a neutral atom, the number of protons and electrons are the same.
In an anion, such atoms have gained electrons.
For sulfide anion, the number of electrons will increase by 2, giving a total of 18 electrons.
The electronic configuration will then be:
S²⁻ = 1s² 2s² 2p⁶ 3s² 3p⁶
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It's an element
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It has all the chemical elements organized by atomic #, from the element w the lowest atomic # , hydrogen, the element w the highest atomic # & by oganesson
Answer:
Explanation: in exothermic reaction heat is released out
In endothermic reaction heat is absorbed