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Leokris [45]
3 years ago
11

The sea water has 8.0x10^-1 cg of element strontium. Assuming that all strontium could be recovered, how many grams of strontium

could be obtained from 9.84x10^8 cubic meter of seawater. Assuming the density of sea water is 1.0g/mL.
Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

984 grams of strontium will be recovered from 9.84x10^8 cubic meter of seawater.

Explanation:

From the question data given is :

volume of strontium in sea water= 9.84x10^8 cubic meter

(1 cubic metre = 1000000 ml)

so 9 .84x10^8 cubic meter

 \frac{9 .84x10^8}{1000000}      = 984 ml.

density of sea water = 1 gram/ml

from the formula mass of strontium can be calculated.

density = \frac{mass}{volume}

mass = density x volume

mass = 1 x 984

         = 984 grams of strontium will be recovered.

98400 centigram of strontium will be recovered.

Strontium is an alkaline earth metal and is highly reactive.

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Here we have to calculate the amount of SO_{4}^{2-} ion present in the sample.

In the sample solution 0.122g of SO_{4}^{2-} ion is present.

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K₂SO₄ = 2K⁺ +  SO_{4}^{2-}

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Thus, BaCl₂+  SO_{4}^{2-} = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and  K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of  SO_{4}^{2-} ion is precipitated in this reaction.  

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We know the molecular weight of sulfate ion (SO_{4}^{2-}) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present.

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Answer : The atom with the same number of neutrons as ^{12}C is, ^{11}B

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Atomic mass number = 12

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Number of neutrons = Atomic mass number - Atomic number = 12 - 6 = 6

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Atomic mass number = 9

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Atomic number = Number of protons = Number of electrons = 4

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Number of neutrons = Atomic mass number - Atomic number = 14 - 7 = 7

Therefore, the atom with the same number of neutrons as ^{12}C is, ^{11}B

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