Yes i believe so because it is clear of toxins and bacteria
Answer:
electrical
Explanation:
they are working together
Answer:
4.1 moles
Explanation:
Applying
PV = nRT................ equation 1
Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = Temperature.
make n the subject of the equation
n = PV/RT.............. Equation 2
From the question,
Given: V = 35 L , P = 2.8 atm, T = 15 °C = (15+273) = 288 K, R = 0.083 L.atm/K.mol
Substitute these values into equation 2
n = (35×2.8)/(0.083×288)
n = 4.1 moles
Answer:
D. Al(s) + O₂(g) → Al₂O₃(s)
Explanation:
Aluminum is a solid metal, so it is written as Al(s).
Oxygen is a diatomic gas, so we write this compound as O₂(g).
Aluminum oxide has the formula Al₂O₃ because in oxides the oxidation number of oxygen atom is -2 and for aluminum, the oxidation number is 3. Thus, we write this compound as Al₂O₃(s).
Now, we have to found the chemical equation in which the reactants (left side) are Al(s) and O₂(g) while the product (right side) is Al₂O₃(s). From the options, we can see that the correct is (D):
Al(s) + O₂(g) → Al₂O₃(s)
Answer:
0.0826 of the volume in the container is actually occupied by Ar atoms
Explanation:
First we find volume occupied by 1 mole the gas using Ideal gas equation
PV = nRT
Given:
P - 230 atm
R - 0.0821 atmL/molK
T - 0 C or 273 K
n - 1
V - Vg (Volume occupied by 1 mole of gas)
Therefore,
Vg = 1 * 0.0821 * 273 / 230 = 0.09745 L
Then we find the volume actually occupied by 1 mole of Ar atoms - Va
b = 4Va
Therefore,
Va = 0.0322 / 4 = 0.00805 L
The fraction of the volume in the container actually occupied by Ar atoms is
= = 0.0826
Therefore, 0.0826 of the volume in the container is actually occupied by Ar atoms