Answer:
Step-by-step explanation:
12a-37 > 0 ...(1)
6a ≤ 42....(2)
by (1) : a ≤ 7 but a is the integer number so : a =1 ; a =2 : a =3 : a=4 ; a = 5
a = 6 and a = 7
1) cas : a = 1 by (2) : 12(1) -37 > 0 -25 > 0 ...... false
2) cas : a = 2 by (2) : 12(2) -37 > 0 -13 > 0 ...... false
3) cas : a = 3 by (2) : 12(3) -37 > 0 -1 > 0 ...... false
4) cas : a = 4 by (2) : 12(4) -37 > 0 11 > 0 ...... true
5) cas : a = 5 by (2) : 12(5) -37 > 0 23> 0 ...... true
6) cas : a =6 by (2) : 12(6) -37 > 0 35 > 0 ...... true
7) cas : a = 7 by (2) : 12(7) -37 > 0 47 > 0 ...... true
all the integer solutions to each system of the inequalities: 4 ; 5; 6: 7 .
