1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yanalaym [24]
3 years ago
6

What cross-section is formed when a place slices a rectangular pyramid parallel to its base?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
3 0
4 I think a triangle
You might be interested in
Describe how ∠PTQ and ∠QTS in the figure are related.
timurjin [86]

Answer:

their unrelated

Step-by-step explanation:

might look similar but very different from each other

8 0
3 years ago
Help!! I'm confused and need help quick!
sergejj [24]
Option 4 with the y-intercept at (0,-3)
4 0
3 years ago
Read 2 more answers
Start with k, add 2, multiply by 6, then subtract 8. Please answer its URGENT! needed NOW ​
adelina 88 [10]
The answer is 4 because k+2 would be 2 then times by 6 which is 12 then subtract 8 would be 4
3 0
2 years ago
Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.
FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

\rho = \sqrt{x^{2}+y^{2}+z^{2}}

\phi = cos^{-1}\frac{z}{\rho}

For angle θ:

  • If x > 0 and y > 0: \theta = tan^{-1}\frac{y}{x};
  • If x < 0: \theta = \pi + tan^{-1}\frac{y}{x};
  • If x > 0 and y < 0: \theta = 2\pi + tan^{-1}\frac{y}{x};

Calculating:

a) (4,2,-4)

\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}} = 6

\phi = cos^{-1}(\frac{-4}{6})

\phi = cos^{-1}(\frac{-2}{3})

For θ, choose 1st option:

\theta = tan^{-1}(\frac{2}{4})

\theta = tan^{-1}(\frac{1}{2})

b) (0,8,15)

\rho = \sqrt{0^{2}+8^{2}+(15)^{2}} = 17

\phi = cos^{-1}(\frac{15}{17})

\theta = tan^{-1}\frac{y}{x}

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = \frac{\pi}{2}

c) (√2,1,1)

\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}} = 2

\phi = cos^{-1}(\frac{1}{2})

\phi = \frac{\pi}{3}

\theta = tan^{-1}\frac{1}{\sqrt{2} }

d) (−2√3,−2,3)

\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}} = 5

\phi = cos^{-1}(\frac{3}{5})

Since x < 0, use 2nd option:

\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }

\theta = \pi + \frac{\pi}{6}

\theta = \frac{7\pi}{6}

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

r=\sqrt{x^{2}+y^{2}}

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

r=\sqrt{4^{2}+2^{2}} = \sqrt{20}

\theta = tan^{-1}\frac{1}{2}

z = -4

b) (0, 8, 15)

r=\sqrt{0^{2}+8^{2}} = 8

\theta = \frac{\pi}{2}

z = 15

c) (√2,1,1)

r=\sqrt{(\sqrt{2} )^{2}+1^{2}} = \sqrt{3}

\theta = \frac{\pi}{3}

z = 1

d) (−2√3,−2,3)

r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}} = 4

\theta = \frac{7\pi}{6}

z = 3

5 0
3 years ago
If x to the 2nd power equal 60, What is the value of x
Sedaia [141]

Answer:

7.745

Step-by-step explanation:

Square root of 60 equals X.

5 0
3 years ago
Other questions:
  • What’s the correct answer for this?
    5·1 answer
  • 7 times as many as 9 is
    6·1 answer
  • What is the gcf of 12 and 8
    14·2 answers
  • Rodney bought a 25-pound bag of dog food. His dog ate 10 2/5 pounds of the food in the first month and 10 4/5 pounds in the seco
    10·2 answers
  • Widget Indutries had stock that sold at 36 5/8 points. The stock rose 7 1/4 points. What is the new price?
    14·1 answer
  • If M ⊥ N and L ∥ M, then _____
    13·1 answer
  • What W is, to make it a true statement
    13·2 answers
  • Help me with this one !!!!!
    14·1 answer
  • Solve the equation for x. Plz help
    5·1 answer
  • How do you solve this limit of a function math problem? ​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!