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Tamiku [17]
4 years ago
7

If the aspect ratio of a chalkboard is 8:6 and the width is 9in, what is the length of the eraser?

Mathematics
1 answer:
KIM [24]4 years ago
6 0
I believe it's A. Sometimes you have to take an educated guess.
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LESSON 23-1 PRACTICE
monitta

Answer:

2

Step-by-step explanation:

2 tuijnbb

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3 years ago
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231 m 31 cm -14 m 48cm
frozen [14]
296 cm is your answer Cody. A easier way to do this question with coming on to brainly. Is add all the positive Integers OR Numbers together and then add all the negative numbers together. Then subtract the negative numbers from the positive. Something like this.

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3 years ago
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1/4+2/3-1/2= how do I solve this
Ann [662]

Answer:

5/12

Step-by-step explanation:

First you add 1/4+2/3.

You need to change the denominator so that they are equal to each other

If you multiply the 1/4 by 3/3 you will get 3/12 which is equal to 1/4

Then you need to do the same to 2/3. This time you need to multiply it by 4/4 to get the same denominator which will be 2/3*4/4=8/12

Then you add 3/12+8/12=11/12. You don't need to add the denominator.

After this you will need to subtract 11/12 and 1/2. This time you need to only change the denominator for 1/2.

You multiply the denominator and numerator by 6/6 to 1/2 and you will get 6/12 then you are going to subtract 11/12-6/12 and you will get 5/12

6 0
3 years ago
PLEASE HELP ME ASAP I REALLY NEED HELP!!!
padilas [110]

1) \overline{UP}

2) \overline{UP} \cong \overline{UP}

3) \overline{UR}

4) \overline{PR}

5) \triangle OUP \cong \triangle RUP by SSS

6) CPCTC

7 0
2 years ago
20 points help plz.
Andrews [41]
This area is equal to the sum of a circle with a radius of 5/2 in and a rectangle 5 by 15 in so:

A=πr^2+xy

A=π(2.5)^2+5*15

A=6.25π+75 in^2

A≈94.63 in^2  (to nearest hundredth) so

A≈95 in^2 (to nearest whole square inch)
8 0
3 years ago
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