Question

How do you solve 4x^2 - 8x + 4 = 0 as completing the square? Is there a solution?

Answer 1

Answer:

1

Step-by-step explanation:

Yes, there is a solution! You first look for a common factor to factor away. Observing, you see that there is common multiple of 4, so your equation becomes $4(x^2-2x+1)=0$. Dividing away the 4, we  get $x^2-2x+1=0$. From here, we can complete the square: $(x-\frac{2}{2})^2-\frac{2}{2}+1=0$ which is equal to $(x-1)^2=0$. When x=1, both sides of the equation equal 0, so x=1.