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3 years ago

I need help please, I dont know how to do this

Mathematics

1 answer:

Oliga [24]3 years ago

3 0

Answer:

Step-by-step explanation:

Odd numbers backwards - 9, 7, 5, 3

1 = -2+9=7

2 = -1+7=6

3 = 0+5=5

4 = 1 +3=4

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Write the decimal equivalent for this fraction 70/100

d1i1m1o1n [39]

Answer:

0.7 is the decimal equivalent to 70/100.

Step-by-step explanation:

You can just do the numerator (70) divided by the denominator (100): 70÷100 = 0.7

8 0

2 years ago

Can you help me please with this question

GREYUIT [131]

Answer:

132

Step-by-step explanation:

You can tell it is 132 from <ABC because the whole angle is a 180 degree angle now subtract 180-48 which is 132. please give me brainiest

6 0

3 years ago

Last one, So so sorry!

zvonat [6]

C and D are the same, so its between A and B, which concludes your answer should be B

8 0

3 years ago

Read 2 more answers

HELP PLEASE what is the slope of the line graphed above?

Aliun [14]

Answer:

Step-by-step explanation:

slope = rise /run

from point (2, 0) to point (-2, 2) you rise 2 and run -4 so m= 2/-4 = -1/2

3 0

3 years ago

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

5 0

3 years ago