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Advocard [28]
3 years ago
15

You and a friend each drive 53 km to the same destination. You travel at 88.8 km/h and your friend at 92.6 km/h. How long will y

our friend wait for you at the end of the trip?
Physics
1 answer:
Setler [38]3 years ago
5 0

Answer:

1.5 minutes

Explanation:

The time it takes for you to drive a distance of 53km at 88.8 km/h is

t = s/v = 53 / 88.8 = 0.5968 hours

Similarly the time it takes for your friend to drive a distance of 53km at 92.6 km/h is

53 / 92.6 = 0.572 hours

Obviously since it takes less time for your friend, he will arrive first if both of you start at the same time. His waiting time would be

0.5968 - 0.572 = 0.0245 hours or 0.0245 * 60 = 1.5 minutes

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Which of the following to all food chains depend on in an ecosystem
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Answer:

The sun is the ultimate source of energy for all food chains. Through the process of photosynthesis, plants use light energy from the sun to make food energy. Energy flows, or is transferred through the system as one organism consumes another.

8 0
3 years ago
Which group's right to vote is protected by the Nineteenth Amendment? Question 7 options: African Americans Native Americans 18-
lisabon 2012 [21]

7. The nineteenth amendment protects the right to vote of 18 year old women.

8.The 24th amendment eliminated poll taxes and increases voting rights in the United States.

9.National voter Registration allowed the option for adults to register vote when they obtain or renew  a driver's license.

10.Three steps in voting process are registering to vote, preparing to vote and casting a ballot.

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4 0
3 years ago
Read 2 more answers
At the outer edge of a rotating space habitat, 130 m from the center, the rotational acceleration is g. What is the rotational a
enyata [817]

Answer:

Explanation:

Given:

R1 = 130 m

R2 = 65 m

w^2R = g

Assume, g = 9.81 m/s^2

w^2 = 9.81/130

w = 0.275 rad/s

At R2 = 65 m

g = w^2R

= (0.275^2) × 65

= 4.905 m/s^2

In conclusion,

g × R = k

g1/R1 = g2/R2

g2 = (g1 × 65)/130

= g1 ×1/2

= g1/2

6 0
3 years ago
Consider three scenarios in which a particular box moves downward under the pull of gravity :
luda_lava [24]

Answer:

1. True  WA > WB > WC

Explanation:

In this exercise they give work for several different configurations and ask that we show the relationship between them, the best way to do this is to calculate each work separately.

A) Work is the product of force by distance and the cosine of the angle between them

    WA = W h cos 0

   WA = mg h

B) On a ramp without rubbing

     Sin30 = h / L

     L = h / sin 30

     WB = F d cos θ  

     WB = F L cos 30

     WB = mf (h / sin30) cos 30

     WB = mg h ctan 30

C) Ramp with rubbing

    W sin 30 - fr = ma

   N- Wcos30 = 0

   W sin 30 - μ W cos 30 = ma

    F = W (sin30 - μ cos30)

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   Wc = mg (1 - μ ctan30) h

When we review the affirmation it is the work where there is rubbing is the smallest and the work where it comes in free fall at the maximum

Let's review the claims

1. True The work of gravity is the greatest and the work where there is friction is the least

2 False. The job where there is friction is the least

3 False work with rubbing is the least

4 False work with rubbing is the least

5 0
4 years ago
How does kinetic energy connect or relate to Newtons second law of motion?
Orlov [11]
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kinetic energy is energy that an object posses while in motion and to get that it must have potential energy.</span>
8 0
3 years ago
Read 2 more answers
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