The magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.
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Magnitude of required force to stop the weight</h3>
The magnitude of the force required to stop the weight in 0.333 seconds is calculated by applying Newton's second law of motion as shown below;
F = ma
F = m(v/t)
F = (mv)/t
F = (5 x 4.5)/0.333
F = 67.6 N
Thus, the magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.
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If you give it unbalanced force it would go up and if you can't give it enough it will stay a balanced force
Answer:
Explained below.
Explanation:
For a boat or any object to float on water, it's density must be less than that of water.
Now, when the maximum capacity of people to be carried by the boat is exceeded, it's possible that the maximum mass of people will also be exceeded depending on the mass of the people in the boat.
Now, we know that; density = mass/volume.
Thus, the higher the mass of the people, the higher the density and the higher the density, the more likely it is to be above that of water and the more likely it is to sink.
Answer:
Explanation:
Natural length of the string is given as
length of the string while block is hanging on it
extension in length is given as
now we have strain in the string is given as
similarly we will have cross-sectional area of the string is given as
now the stress in the string is given as
Now Young's Modulus is given as
The object with the mass ok 1kg will move more quickly because it is lighter than the 100kg object
