The work done to stop the car is -208.33 kJ
From work-kinetic energy principles, the change in kinetic energy of the car ,ΔK equals the work done to stop the car, W.
W = ΔK = 1/2m(v'² - v²) where
- m = mass of car = 1500 kg,
- v = initial velocity of car = 60 km/h = 60 × 1000 m/3600 s = 16.67 m/s and
- v' = final velocity of car = 0 m/s (since the car stops).
<h3 /><h3>Calculating the work done</h3>
Substituting the values of the variables into the equation, we have
W = 1/2m(v'² - v²)
W = 1/2 × 1500 kg(v(0 m/s)² - (16.67 m/s)²)
W = 750 kg(0 (m/s)² - 277.78 (m/s)²)
W = 750 kg(- 277.78 (m/s)²)
W = -208333.33 J
W = -208.33333 kJ
W ≅ -208.33 kJ
So, the work done to stop the car is -208.33 kJ
Learn more about work done here:
brainly.com/question/9821607
Answer: a = 1, b = 9, c = 6, d = 4
Explanation:
With no velocity, total mechanical energy is all gravity potential energy
PE = mgh = 80.0(9.81)(25) = 19,620 J = 1.96e4 J
Answer:
Acceleration = 1.428m/s2
Tension = 102.85N
Explanation:
The detailed solution is attached
This drag force is always opposite to the object's motion, and unlike friction between solid surfaces, the drag force increases as the object moves faster.
