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nikklg [1K]
3 years ago
14

Help plz help help help

Mathematics
1 answer:
PtichkaEL [24]3 years ago
3 0

Answer:

its so blurry

Step-by-step explanation:

grrrr

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How do you solve <br> 8|x+2|-6=5|x+2|+3
sergejj [24]

Answer:

x = 1 or x = -5

Step-by-step explanation:

Solve for x over the integers:

8 abs(x + 2) - 6 = 5 abs(x + 2) + 3

Subtract 5 abs(x + 2) - 6 from both sides:

3 abs(x + 2) = 9

Divide both sides by 3:

abs(x + 2) = 3

Split the equation into two possible cases:

x + 2 = 3 or x + 2 = -3

Subtract 2 from both sides:

x = 1 or x + 2 = -3

Subtract 2 from both sides:

Answer:  x = 1 or x = -5

7 0
3 years ago
What is the correct solution to (x+2)(x+5)​
elena-s [515]

Answer:

x^2+7x+10

Step-by-step explanation:

multiply the first by first and first by second

multiply the second by first and second by second

7 0
3 years ago
A pyramid and a cone are both 8 centimeters tall and have the same volume.
notka56 [123]

Answer:

D. The horizontal cross-sections of the prisms at the same height must have the same area.

Step-by-step explanation: I dont know what the guy above is saying but this is the right answer

4 0
2 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
3 years ago
Help again please?............
zheka24 [161]
18.72
so the answer is d
4 0
3 years ago
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