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Marta_Voda [28]
3 years ago
5

HELP ME PLEASE!! I WILL MARK YOU AS A BRAINLIEST!!

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0

Answer:

The original price was $25

Step-by-step explanation:

where p is the original price of the shirt, the sale price of the shirt is .80p.

the sale price of the shirt is p - 5.

so you can use this equation:

.80p = p - 5

now solve for p.

.80p - 1p = -5

-.20p = -5

p = 25.

so the original price was $25 and the sale price was $20.

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He ------- daily for a year now. <br><br> a) exercises b) was exercising c) has been exercising
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Answer: C: has been exercising
6 0
2 years ago
Suppose that Adam rolls a fair six-sided die and a fair four-sided die simultaneously. Let AAA be the event that the six-sided d
myrzilka [38]

The question is incomplete. Here is the complete question.

Suppose that Adam rolls a fair six-sided die and a fair four-sided die simultaneously. Let A be the event that the six-sided die is an even number and B be the event that the four-sided die is an odd number. Using the sample space of possible outcomes below, answer each of the following questions.

What is P(A), the probabillity that the six-sided die is an even number?

What is P(B), the probability of the four-sided die is an odd number?

What is P(A and B), the probability that the six-sided die is an even number  <em>and</em> the four-sided die is an odd number?

Are events A and B independent?

a) Yes, events A and B are independent events.

b) No, events A and B are not independent events.

Answer: P(A) = 1/2

P(B) = 1/2

P(A and B) = 1/4

a) Yes, events A and B are independent events.

Step-by-step explanation: The event A is related to a six-sided die, so total possibilities is 6.

For a six-sided die to show a even number, there are 3 possibilities: (2,4,6)

so, P(A) = 3/6 = 1/2

The event B is for a 4-sided die, i.e. total possibilities is 4.

To show an odd number, there are 2 possibilities: (1,3).

Then, P(B) = 2/4 = 1/2

Now, the probability of occuring A and B is:

P(A and B) = P(A).P(B)

P(A and B) = 1/2*1/2

P(A and B) = 1/4

The events are <u>independent</u> events because the probability of A happening does not influence the occuring of event B.

3 0
4 years ago
(b) Use the right-hand rule to decide whether the components of a × b are positive, negative, or 0.
Gekata [30.6K]

(a)

Given:  

\vec{a} is in xy plane and \vec{b} is in the direction of k.

|a|=6 units, |b|=3 and θ = 90°

|a × b| = |a| × |b| sinθ  

          = |a| × |b| sin90°  

          = 6 × 3 × 1  

|a × b| = 18  

(b)

Let \vec{c}=\vec{a} \times \vec{b}

\vec{c} is perpendicular to both \vec{a} \text { and } \vec{b}.

In this case,

x-component of \vec{a} \times \vec{b} is positive.

y-component of \vec{a} \times \vec{b} is negative.

z-component of \vec{a} \times \vec{b} is zero.

5 0
3 years ago
Algebra (50 pts) i need an answer quick tysm and have a blessed day
Artemon [7]

Answer:

? = 1

Step-by-step explanation:

3/8r - 1/4r + 2s

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Answer:

a) the answer if the substitute is 300

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