Use the function Y=2x^2+3x+7 to answer the following questions

The amount of money Chaz earned for walking dogs is given in the table. Can the relationship be described by a constant rate? Ex

mojhsa [17]

Answer:

Yes, the relationship can be described by a constant rate of $18.75 per dog

Step-by-step explanation:

see the attached figure to better understand the problem

Let

x ----> the number of dogs

y ---> the amount of money earned

we have the points

$(6,112,50), (8,150), (11,206.25)$

step 1

Find the slope with the first and second point

$(6,112,50), (8,150)$

$m=(150-112.50)/(8-6)=18.75$

step 2

Find the slope with the first and third point

$(6,112,50), (11,206.25)$

$m=(206.25-112.50)/(11-6)=18.75$

Compare the slopes

The slopes are the same

That means, that the three points lies on the same line

therefore

Yes, the relationship can be described by a constant rate of $18.75 per dog

7 0

3 years ago

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0

2 years ago

What is the quotient? Will give brainliest and will report absurd answers.

coldgirl [10]

Answer:

D

Step-by-step explanation:

When dividing fractions, multiply the first number by the reciprocal of the second number

2/5 ÷ 1/3

First, find the reciprocal of the second number: 1/3

To find the reciprocal, flip the numerator (top number) and denominator (bottom number)

1/3-->3/1

Now, multiply 2/5 and 3/1

2/5 * 3/1

Multiply across the numerators and denominators

6/5

5 0

3 years ago

Can someone tell me what is 8/9+3/5

I am Lyosha [343]

Okay I am going to explain to you and show you how to get the correct answer.

Fist you need to find the Greatest common factor which is 45 because 5×9=45

8/9=40/45

+3/5=27/45
__________
67/45 is reduced to 1 22/45
5 goes into 45 9 times so 3 times 7 equals 27 and 9 goes into 45 5 times so 8 times 5 equals 40 you add both numbers up and get 67. 67 can't go into 45 so you subtract 67 from 45. 45 goes into 67 1 time so that is your whole the number. 22 is left over so that is your numerator. The denominator remains the same.

5 0

3 years ago

Your patio is 12 feet by 15 feet. After remodeling, the new dimensions are 18 feet by 22 feet. By how many square feet have you

Mashutka [201]

<h3>Answer: 216 square feet</h3>

Work Shown:

Old area = 12*15 = 180 square feet

New area = 18*22 = 396 square feet

Difference = New - Old = 396 - 180 = 216

The patio's area increased by 216 square feet.

8 0

2 years ago