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a_sh-v [17]
3 years ago
15

Find the length of side AC

Mathematics
1 answer:
miv72 [106K]3 years ago
8 0
We know that

sin 45°=√2/2
and
 in the triangle ABC
sin 45°=AC/AB----------> AC=AB*sin 45°--------> 5*√2/2

the answer is
 the option D) AC=5√2/2
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What is the input-output table for the function f(x) = 3x^2-x+4
mojhsa [17]

Answer:

Step-by-step explanation:

The input-output table can be made by putting value of x and finding the value of f(x)

f(x) = 3x^2-x+4

f(0) = 3(0)^2-0+4 = 0-0+4 = 4

f(1) = 3(1)^2-1+4 = 3-1+4 = 2+4 =6

f(2) = 3(2)^2-2+4 = 3(4)-2+4 = 12-2+4 = 10+4 = 14

f(3) = 3(3)^2-3+4 = 3(9)-3+4 = 27-3+4 = 24+4 = 28

So put value of x and find f(x) and fill the input-output table.

x  f(x)

0   4

1    6

2   14

3    28

3 0
3 years ago
The shirt costs twice as much as the shoes. Together, they cost more than $200. What is the minimum cost for each item? (Round t
miskamm [114]
$200 because you can't round toe the nearest dollar

4 0
4 years ago
Read 2 more answers
ILL GIVE BRAINLIEST!!!!!!<br><br> Please explain!! Thank you!!
Bumek [7]

Answer:

The answer would be C

Step-by-step explanation:

He started at 250 lbs. He is losing 3 lbs every week.

So it would be y=250(beginning weight)-3x(how much he's losing every week)

Hope this helped :)

4 0
3 years ago
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brooke found the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form as follows​
Goryan [66]

Answer:

The equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

Step-by-step explanation:

Equation of line passing through the points (-7,25) and (-4,13) in slope-intercept form.

The general equation of slope-intercept form is: y=mx+b

First we need to find slope

The formula used for finding slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We are given: x_1=-7, y_1=25, x_2=-4, y_2=13

Putting values in formula and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{13-25}{-4-(-7)}\\Slope=\frac{13-25}{-4+7}\\Slope=\frac{-12}{3}\\Slope=-4

So, slope m= -4

Now finding y-intercept

Using slope m=-4 and point (-7,25) we can find y-intercept

y=mx+b\\25=-4(-7)+b\\25=28+b\\b=25-28\\b=-3

So, y-intercept b =-3

Now, the equation of required line having slope m=-4 and  y-intercept b=-3 is:

y=mx+b\\y=-4x-3

So, the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

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The answer is in the photo.

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