Question

brooke found the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form as follows​

Answer 1

Answer:

The equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is $\mathbf{y=-4x-3}$

Step-by-step explanation:

Equation of line passing through the points (-7,25) and (-4,13) in slope-intercept form.

The general equation of slope-intercept form is: $y=mx+b$

First we need to find slope

The formula used for finding slope is: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We are given: $x_1=-7, y_1=25, x_2=-4, y_2=13$

Putting values in formula and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{13-25}{-4-(-7)}\\Slope=\frac{13-25}{-4+7}\\Slope=\frac{-12}{3}\\Slope=-4$

So, slope m= -4

Now finding y-intercept

Using slope m=-4 and point (-7,25) we can find y-intercept

$y=mx+b\\25=-4(-7)+b\\25=28+b\\b=25-28\\b=-3$

So, y-intercept b =-3

Now, the equation of required line having slope m=-4 and  y-intercept b=-3 is:

$y=mx+b\\y=-4x-3$

So, the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is $\mathbf{y=-4x-3}$