Find a general solution to the differential equation â6yâ²=1+x+y+xy by solving the equation and then applying the initial condit
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ANSWER
The coordinates of the image are (2,2)
EXPLANATION
The mapping for a reflection across the line y=k is :
We want to find the image of the point (2,-4) after a reflection in the line y=-1.
In this case k=-1.
This simplifies to,
Hence the image is (2,2)