Find a general solution to the differential equation â6yâ²=1+x+y+xy by solving the equation and then applying the initial condit
1 answer:
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Answer: Vertex = (2, -15) 2nd point = (0, -3)
<u>Step-by-step explanation:</u>
g(x) = 3x² - 12x - 3
= 3(x² - 4x - 1)
a=1 b=-4 c=-1
Find the x-value of the vertex by using the formula for the axis of symmetry:
= 2
Find the y-value of the vertex by plugging the x-value (above) into the given equation: g(x) = 3x² - 12x - 3
g(2) = 3(2)² - 12(2) - 3
= 12 - 24 - 3
= -15
So, the vertex is (2, -15) ← PLOT THIS COORDINATE
Now, choose a different x-value. Plug it into the equation and solve for y. <em>I chose x = 0</em>
g(0) = 3(0)² - 12(0) - 3
= 0 - 0 - 3
= -3
So, an additional point is (0, -3) ← PLOT THIS COORDINATE