Answer:
Explanation:
At the cathode
In case of molten AgI
Silver will be collected
In case of molten LiI
lithium will be collected
in case of aqueous LiI,
hydrogen gas will be collected as reduction potential of H⁺ is more than Li⁺
in case of aqueous AgI,
Silver will be obtained at cathode because reduction potential of silver is more than H⁺
At the Anode
In case of molten NaBr
Bromine will be collected
In case of molten NaF
Fluorine will be collected
in case of aqueous NaBr ,
Bromine will be collected as reduction potential of Br⁻ is less than O⁻²
in case of aqueous NaF ,
oxygen will be obtained because reduction potential of F⁻ is more than O⁻² .
Answer:
The answer to your question is 6.54 g of H₂O
Explanation:
Data
mass of water = ?
mass of carbon dioxide = 16 g
Balanced chemical reaction
H₂CO₃ ⇒ H₂O + CO₂
Process
1.- Calculate the molar mass of the products
H₂O = (1 x 2) + (1 x 16) = 2 + 16 = 18 g
CO₂ = (1 x 12) + (16 x 2) = 12 + 32 = 44 g
2.- Use proportions and cross multiplication to solve this problem.
18 g of H₂O -------------------- 44 g of CO₂
x -------------------- 16 g of CO₂
x = (16 x 18) / 44
x = 288/44
x = 6.54 g of H₂O
Answer:
<em>It Is Transitional Energy.</em>
Explanation: <em>I Took The Quiz And Got It Wrong. It Showed That Transitional Energy Was The Correct Answer. </em>
B ) MgCl2(aq) is the correct answer