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4 years ago

What is the definition of thermal expansion

Chemistry

1 answer:

MissTica4 years ago

8 0

Answer:

Thermal expansion is the tendency of matter to change its shape, area, and volume in response to a change in temperature.

Explanation:

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N2 + 3H2 + 2NH3 .

HACTEHA [7]

Answer:

Explanation:

7 0

3 years ago

If a liquor law is violate the liquor authority can issue a citation today

Basile [38]

If a liquor law is violated, the liquor authority can issue a citation of fine. The other consequence of liquor law violation is Liquor- license suspension.

<h2>What is liquor law?</h2>

Liquor law is also called Alcohol laws. Alcohol laws are the laws which are related to the manufacture, use and the sale of alcohol or alcoholic beverages that contains ethanol. If this law is violated, the liquor authority can issue a fine as well as the suspension of Liquor- license so we can conclude that fine and Liquor- license suspension are the consequences of violation of liquor law.

Learn more about law here: brainly.com/question/820417

8 0

2 years ago

A car uses stored chemical energy in gasoline to move. The engine changes chemical energy into heat and ____ energy to power the

Salsk061 [2.6K]

I want to say Mechanical energy. Do you have answer choices?

6 0

4 years ago

A chemist must prepare 800.0mL of sodium hydroxide solution with a pH of 12.10 at 25°C. She will do this in three steps: Fill a

AnnZ [28]

Answer:

0.42 g

Explanation:

pH = 12.10 (25 °C)

V = 800.0 mL = 0.800 L

To find the mass of sodium hydroxide (NaOH) we can use the pH:

$14 = pH + pOH$

$pOH = 14 - pH = 14 - 12.10 = 1.90$

$pOH = -log ([OH^{-}])$

$[OH]^{-} = 10^{-pOH} = 10^{-1.90} = 0.013 M$

Now, we can find the number of moles (η) of OH:

$\eta = ([OH]^{-})*V = 0.013 mol/L * 0.800 L = 1.04 \cdot 10^{-2} moles$

Since we have 1 mol of OH in 1 mol of NaOH, the number of moles of NaOH is equal to 1.04x10⁻² moles.

Finally, with the number of moles we can find the mass of NaOH:

$m = \eta * M$

<em>Where M is the molar mass of NaOH = 39.9 g/mol </em>

$m = 1.04 \cdot 10^{-2} moles * 39.9 g/mol = 0.42 g$

Therefore, the mass of sodium hydroxide that the chemist must weigh out in the second step is 0.42 g.

I hope it helps you!

3 0

3 years ago

The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th

OLga [1]

Answer:

ΔH = -162.5 kJ.

Explanation:

Hello.

In this case, we first rearrange the reactions:

ClO(g) + O₃(g) ⇒ Cl(g) + 2O₂(g); ΔH =-122.8 kJ

2O₃(g) ⇒ 3O₂(g); ΔH=-285.3 kJ

O₃(g) + Cl(g) ⇒ ClO(g) + O₂(g); ΔH= ?

Thus, we are going to use the Hess law, as an strategy to rearrange the known chemical reactions and thereby compute the enthalpy of reaction of the unknown one.

1. The first reaction must be inverted in order to obtain chlorine as a reactant in the third one, therefore, the enthalpy of reaction becomes positive:

Cl(g) + 2O₂(g) ⇒ ClO(g) + O₃(g); ΔH = 122.8 kJ

2. Second reaction remains the same:

2O₃(g) ⇒ 3O₂(g); ΔH=-285.3 kJ

Then, we add them to obtain:

Cl(g) + 2O₂(g) + 2O₃(g) ⇒ ClO(g) + O₃(g) + 3O₂(g)

Whereas we can subtract both oxygen and ozone to obtain the third one:

O₃(g) + Cl(g) ⇒ ClO(g) + O₂(g)

Therefore, the enthalpy of reaction turns out:

ΔH = 122.8 kJ + (-285.3 kJ )

ΔH = -162.5 kJ.

Best regards.

4 0

3 years ago