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vladimir1956 [14]
3 years ago
14

What is the definition of thermal expansion

Chemistry
1 answer:
MissTica3 years ago
8 0

Answer:

Thermal expansion is the tendency of matter to change its shape, area, and volume in response to a change in temperature.

Explanation:

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(b) what is the major product of the reaction at very low temperatures?
svlad2 [7]
The reaction is low b/c of  the tempature. that's why.
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How many moles of gold are equivalent to 1.204 × 1024 atoms? 0.2 0.5 2 5
NeTakaya

Answer:

c

Explanation:

How many moles of gold are equivalent to 1.204 × 1024 atoms?

0.2

0.5

2

5

C) 2 Is the correct answer, I took the test and it was correct.

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How much energy does a 445 nm wave of light have? (The speed of light in a
Dahasolnce [82]

Answer:

A

Explanation:

To calculate questions like this, you need to make use of the equation below:

E = hν

E is the energy, h is Planck's constant, and ν is the frequency.

Also, another important formula you need for this question is the following:

ν = c / λ

ν is the frequency, c is the speed of light, and λ is the wavelength.

Therefore, E = hν = hc/λ.

Also remember to convert nm wavelength to meters.

To answer the question, E = hc/λ = ((6.626*10^-34 J•s)(3*10^8 m/s))/(4.45*10-7 m) = 4.42 • 10^-19 J = A

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2 years ago
Red aesthetic and one other thing
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The enthalpy of a pure liquid at 75oC is 100 J/mol. The enthalpy of the pure vapor of that substance at 75oC is 1000 J/mol. What
pentagon [3]

Answer:

900 J/mol

Explanation:

Data provided:

Enthalpy of the pure liquid at 75° C = 100 J/mol

Enthalpy of the pure vapor at 75° C = 1000 J/mol

Now,

the heat of vaporization is the the change in enthalpy from the liquid state to the vapor stage.

Thus, mathematically,

The heat of vaporization at 75° C

=  Enthalpy of the pure vapor at 75° C - Enthalpy of the pure liquid at 75° C

on substituting the values, we get

The heat of vaporization at 75° C = 1000 J/mol - 100 J/mol

or

The heat of vaporization at 75° C = 900 J/mol

8 0
3 years ago
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