<span>The filament of the light bulb will get very hot. This will encourage a chemical reaction with most gases that are surrounding that filament - and the result is that the filament burns out. If the filament is in air, it combines with the carbon of carbon dioxide in the air, and the filament disintegrates. But argon is an inert gas - almost nothing reacts with it. So the filament takes a very long time (theoretically infinity) to burn out. But the bulb cannot contain 100% argon: 99.9% is typical; the remaining 0.1% being air. The bulb manufacturers can control the 'life' of a bulb, based on that principle: they do not want their bulbs to last forever!</span>
62.23 = 1512.5001499999998 moles
Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.
Explanation :
First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.
As, 207.2 g of lead contains
atoms
So, 5.5 g of lead contains
atoms
and,
As, 118.71 g of lead contains
atoms
So, 94.5 g of lead contains
atoms
Now we have to calculate the percent composition of Pb and Sn in atom.
![\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7BComposition%20of%20Pb%7D%3D%5Cfrac%7B%5Ctext%7BAtoms%20of%20Pb%7D%7D%7B%5Ctext%7BAtoms%20of%20Pb%7D%2B%5Ctext%7BAtoms%20of%20Sn%7D%7D%5Ctimes%20100)
![\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7BComposition%20of%20Pb%7D%3D%5Cfrac%7B1.59%5Ctimes%2010%5E%7B22%7D%7D%7B%281.59%5Ctimes%2010%5E%7B22%7D%29%2B%284.79%5Ctimes%2010%5E%7B23%7D%29%7D%5Ctimes%20100%3D3.21%5C%25)
and,
![\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7BComposition%20of%20Sn%7D%3D%5Cfrac%7B%5Ctext%7BAtoms%20of%20Sn%7D%7D%7B%5Ctext%7BAtoms%20of%20Pb%7D%2B%5Ctext%7BAtoms%20of%20Sn%7D%7D%5Ctimes%20100)
![\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7BComposition%20of%20Sn%7D%3D%5Cfrac%7B4.79%5Ctimes%2010%5E%7B23%7D%7D%7B%281.59%5Ctimes%2010%5E%7B22%7D%29%2B%284.79%5Ctimes%2010%5E%7B23%7D%29%7D%5Ctimes%20100%3D96.8%5C%25)
Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.
Answer:
hope this helps
Explanation:
glycosidic bond
A covalent bond formed between a carbohydrate molecule and another molecule (in this case, between two monosaccharides) is known as a glycosidic bond (Figure 4). Glycosidic bonds (also called glycosidic linkages) can be of the alpha or the beta type.