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3 years ago

1 point

Chemistry

1 answer:

Genrish500 [490]3 years ago

5 0

With an electronegativity of 0.89, Barium requires the least amount of energy to remove its valence electrons.

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The cell potential of the following electrochemical cell depends on the gold concentration in the cathode half-cell: Pt(s)|H2(g,

Masja [62]

Answer: The concentration of $Au^{3+}$ in the solution is $1.87\times 10^{-14}M$

Explanation:

The given cell is:

$Pt(s)|H_2(g.1atm)|H^+(aq.,1.0M)||Au^{3+}(aq,?M)|Au(s)$

Half reactions for the given cell follows:

Oxidation half reaction: $H_2(g)\rightarrow 2H^{+}(1.0M)+2e^-;E^o_{H^+/H_2}=0V$ ( × 3)

Reduction half reaction: $Au^{3+}(?M)+3e^-\rightarrow Au(s);E^o_{Au^{3+}/Au}=1.50V$ ( × 2)

Net reaction: $3H_2(s)+2Au^{3+}(?M)\rightarrow 6H^{+}(1.0M)+2Au(s)$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=1.50-0=1.50V$

To calculate the concentration of ion for given EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[H^{+}]^6}{[Au^{3+}]^2}$

where,

$E_{cell}$ = electrode potential of the cell = 1.23 V

$E^o_{cell}$ = standard electrode potential of the cell = +1.50 V

n = number of electrons exchanged = 6

$[Au^{3+}]=?M$

$[H^{+}]=1.0M$

Putting values in above equation, we get:

$1.23=1.50-\frac{0.059}{6}\times \log(\frac{(1.0)^6}{[Au^{3+}]^2})$

$[Au^{3+}]=1.87\times 10^{-14}M$

Hence, the concentration of $Au^{3+}$ in the solution is $1.87\times 10^{-14}M$

7 0

3 years ago

An element has 3 electrons, 3 protons and 4 neutrons. What will be its atomic number and mass number? (

stiv31 [10]

Answer:

its atomic number will be 3 and it's mass number will be 7. it is lithium

8 0

2 years ago

The best way seperate salt fron wateris with the use of

ExtremeBDS [4]

You can boil or evaporate the water and the salt will be left behind as a solid. If you want to collect the water, you can use distillation. This works because salt has a much higher boiling point than water. One way to separate salt and water at home is to boil the salt water in a pot with a lid. So, I would say maybe oil.

6 0

2 years ago

Please help! due soon!

nekit [7.7K]

Answer:

I think it's

there are the same number of molecules on each side of the equation, then a change of pressure makes no difference to the position of equilibrium

7 0

2 years ago

In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance. What is the total resistance?

Sauron [17]

Answer:

17 ohms

Explanation:

Given that,

In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance.

We need to find the total resistance of the circuit.

The equivalent resistance for series combination is given by :

$R_{eq}=R_1+R_2+....$

For 17 light bulbs, the equivalent resistance is given by :

$R_{eq}=R+R+....\text{upto 17 terms}\\\\R_{eq}=17R\\\\=17$

Hence, the total resistance is 17 ohms. Hence, the correct option is (d).

7 0

3 years ago