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ser-zykov [4K]
3 years ago
6

You are making some MES buffer. The pKa of MES is 6.2. You want to make 1 L of a 1 M solution of MES (pH 6.2). You weigh out 1 m

ole of the basic (unprotonated) form of MES and dissolve it in 750 mL water. What would you add to this before you brought the volume to 1 L with water?
Chemistry
1 answer:
sweet [91]3 years ago
5 0

Answer:

To make the buffer you must add 1 mole of MES in the liter of the buffer.

Explanation:

To find pH of the buffer of MES you must use Henderson-Hasselbalch equation:

pH = pKa + log [MES⁻] / [MES]

<em>Where [MES⁻] is molar concentration of unprotoned MES and [MES] molar concentration of the acid</em>

<em />

Replacing:

6.2 = 6.2 + log [1M] / [MES]

<em>Molar concentration of [MES⁻] is 1mol / L = 1M</em>

0 = log [1M] / [MES]

1 = [1M] / [MES]

[MES] = 1M

That means to make the buffer you must add 1 mole of MES in the liter of the buffer

<em />

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8740 joules are required to convert 20 grams of ice to liquid water.

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Q = m\cdot [c\cdot (T_{f}-T_{o})+L_{f}] (1)

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T_{o}, T_{f} - Temperature, measured in degrees Celsius.

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