All categories

3 years ago

There are four springs stretched by the same mass. Spring A stretches 25 cm. Spring B stretches

Physics

1 answer:

juin [17]3 years ago

7 0

Answer:

Spring C

Explanation:

According to Hooke's law, a force require to compress or extend a spring is directly proportional to the distance from its mean position.

The force of compression or expansion of the spring is given by the formula,

F = k x

Where,

k - spring constant. It is the constant value of the particular spring

x - distance of expansion or compression from mean position.

The x value of different spring,

A = 25 cm

B = 10 cm

C = 100 cm

D = 1 cm

The highest value of x for the same mass has the smallest spring constant according to the equation.

Hence, C has the smallest spring constant.

You might be interested in

A child and sled with a combined mass of 50.0 kg slide down a frictionless slope. if the sled starts from rest and has a speed o

Furkat [3]

<span> Using conservation of energy

Potential Energy (Before) = Kinetic Energy (After)

mgh = 0.5mv^2

divide both sides by m

gh = 0.5v^2

h = (0.5V^2)/g

h = (0.5*2.2^2)/9.81

h = 0.25m

</span>

4 0

3 years ago

Read 2 more answers

Two cars collide and come to a complete stop. where did all of their energy go?

MA_775_DIABLO [31]

Most of the energy will be absorbed by the materials that make up the cars, causing them to deform. The energy will also be converted into sound energy, causing a loud bang upon collision. Also, some energy will be converted to thermal energy, which will cause the cars to heat up slightly.

3 0

3 years ago

List 3 quantities of waves.

VARVARA [1.3K]

If you mean like electromagnetic waves then, Mico waves, UV rays, and infrared waves

8 0

4 years ago

Read 2 more answers

Why is it very difficult for astronomers to find objects like planets and asteroids?

mezya [45]

It is difficult for astronomers to find object like planets and asteroids because it takes a lot of time to verify the objects locations and what surrounds a certain object in order to prove and be precise of its location

3 0

4 years ago

A piece of wire 29 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

skelet666 [1.2K]

Answer:

Explanation:

Total length of the wire is 29 m.

Let the length of one piece is d and of another piece is 29 - d.

Let d is used to make a square.

And 29 - d is used to make an equilateral triangle.

(a)

Area of square = d²

Area of equilateral triangle = √3(29 - d)²/4

Total area,

$A = d^{2}+\frac{\sqrt3}{4}\left ( 29-d \right )^{2}$

Differentiate both sides with respect to d.

$\frac{dA}{dt}=2d- \frac{\sqrt3}{4}\times 2(29-d)$

For maxima and minima, dA/dt = 0

d = 8.76 m

Differentiate again we get the

$\frac{d^{2}A}{dt^{2}}= + ve$

(a) So, the area is maximum when the side of square is 29 m

(b) so, the area is minimum when the side of square is 8.76 m

8 0

3 years ago