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insens350 [35]
3 years ago
10

Which of the following is an appropriate receive filter bandwidth for minimizing noise and interference for CW reception?A. 500

Hz
B. 1000 Hz
C. 2400 Hz
D. 5000 Hz
Physics
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer: option A= 500 Hz.

Explanation:

The full meaning of CW is continuous waveform or continuous wave. Continuous waveform during wireless telegraph radio transmission is also known as undamped waves. Around 1920, damped wave spark transmitters were replaced by continuous wave vacuum tube transmitters. Continuous waveform is some wave of constant amplitude and frequency.

Continuous waveform consists of a pure sine wave multiplied with a square wave that's either 0 or 1, corresponding to the keying of the carrier. Continuous waveform receive filters with passband around 500 Hz.

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A tank is filled with an ideal gas at 400 K and pressure of 1.00 atm.
bekas [8.4K]

To find the temperature it is necessary to use the expression and concepts related to the ideal gas law.

Mathematically it can be defined as

PV=nRT

Where

P = Pressure

V = Volume

n = Number of moles

R = Gas constant

T = Temperature

When the number of moles and volume is constant then the expression can be written as

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Or in practical terms for this exercise depending on the final temperature:

T_2 = \frac{P_2T_1}{P_1}

Our values are given as

T_1 = 400K\\P_1 = 1atm\\P_2 = 2atm

Replacing

T_2 = \frac{(2)(400)}{1}\\T_2 = 800K

Therefore the final temperature of the gas is 800K

6 0
3 years ago
What is the easiest way to increase the magnetic force acting on the rotor in an induction motor?
Schach [20]

Answer:

Explanation:

Magnets are of two major forms namely the permanent magnet and the temporary magnets. Temporary magnets magnetizes and demagnetize easily while permanent magnets does not magnetizes and demagnetize easily.

This permanents magnets are applicable in loudspeakers, generators, induction motor etc.

To increase the

The following will tend to increase the magnetic force acting on the rotor in an induction motor.

1. Increasing the strength of the bar magnet. Increase in strength of the magnet will lead to increase in the magnetic force acting on the rotor.

2. Increase in the magnetic line of force also known as the magnetic flux around the magnet will also increase the magnetic force acting on the rotor.

6 0
3 years ago
An electron is ejected from the cathode by a photon with an energy slightly greater than the work function of the cathode. How w
Ksivusya [100]

It will be approximately equal.

<h3>How will the final kinetic energy change?</h3>

We can infer that all of the energy in the electron is Potential energy (PE) because the energy provided by the photon is hardly enough to outweigh the work function.

It will gain kinetic energy (KE) as it advances in the direction of the anode because it is moving through an electric field. All of the PE will have been transformed to KE by the time it reaches the anode.

According to the question

K = hf - W

W = Work function

The energy of photons is comparable. After conversion, there was only a little amount of KE remaining.

Therefore, PE (W) essentially equals KE (K).

It will about be equal.

Learn more about work function here:

brainly.com/question/19595244

#SPJ4

3 0
2 years ago
What is the period of a 4.12 m long pendulum?
lisov135 [29]
Using the equation for period length, you get an answer of about 4.1 seconds.
8 0
3 years ago
A car starts from rest and after 20 seconds it's velocity becomes 108km find the acceleration of the car
andre [41]

Answer:

1.5 km/s²

Explanation:

Given that:

a car starts from rest; it means the initial velocity (u) = 0 km/hr = 0 m/s

after time (t) = 20 seconds

the final velocity = 108 km/hr = 30 m/s

The acceleration (a) of the car can be determined by using the formula:

a = \dfrac{v-u}{t}

a = \dfrac{30\  m/s -0 \ m/s}{20 \ s}

a = \dfrac{30 \  m/s}{20 \ s}

a = 1.5 km/s²

7 0
3 years ago
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