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AleksandrR [38]

3 years ago

11

a sales person works 3 days per week. she earns 1/3 of her pay on monday and 1/4 on tuesday. how much of her pay does she earn o

n Wednesday???

1 answer:

vagabundo [1.1K]3 years ago

3 0

42 percent on wensday because 33 plus 25=58 and 58+42=100

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the speed that a tsunami can travel is modeled by the equation mc025-1.jpg , where s is the speed in kilometers per hour and d i

Flura [38]

The answer is a.0.32 km.

The speed that a tsunami can travel is modeled by the equation is s = 356√d.

It is given:
s = 200 km/h
d = ?

Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562

Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32

Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>

5 0

3 years ago

Read 2 more answers

Calculate the value of x in the equation 2x - 15 =5 - 3×

pshichka [43]

$\bold{2x - 15 = 5 - 3x} \\ \bold{2x + 3x = 15 + 5} \\ \bold{5x =20 } \\ \bold{x = \cancel{ \frac {20}{5} }} \\ \bold{x = 4}$

Hope it helps

3 0

1 year ago

Read 2 more answers

I just need help with this table

Mashutka [201]

Answer:

from the looks of it, all you have to do is, for f(x), is plug it in as an exponent. in order (top to bottom), it should be: 64, 2048, 4096, 8192.

g(x) is being squared and then multiplied, so it should be (from top to bottom): 720, 2420, 2880, 3380

Step-by-step explanation:

6 0

3 years ago

The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h

saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

$P(X=4)=\frac{\lambda^{X}*e^{-\lambda} }{X!} =\frac{5^{4}*e^{-5} }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754$

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))$

Using

$P(X)=\frac{\lambda^{X}*e^{-\lambda} }{X!}$

We get

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\$

The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is

$EV=\lambda*t=5*0.75=3.75$

8 0

3 years ago

At a sports camp, there is one counselor for every 12 campers. If there are 156 campers attending the camp, which equivalent rat

Pepsi [2]

Hello There!

It is 1:12 for counselor to camper
If there are 156 campers, follow these steps:
1 + 12 = 13
156/12 = 13
1 x 13 = 13
12 x 12 = 156
The ratio now is 13:156.
Meaning there are 13 counselors.

Hope This Helps You!
Good Luck :)

- Hannah ❤

5 0

3 years ago