28. Surface Area
This is some sort of house-like model so for every face we see there's a congruent one that's hidden. We'll just double the area we can see.
Area = 2 × ( [14×9 rectangle] + 2[15×9 rectangle]+[triangle base 14, height 6] )
Let's separate the area into the area of the front and the sides; the front will help us for problem 29.
Front = [14×9 rectangle] + [triangle base 14, height 6]
= 14×9 + (1/2)(14)(6) = 14(9 + 3) = 14×12 = 168 sq ft
OneSide = 2[15×9 rectangle] = 30×9 = 270 sq ft
Surface Area = 2(168 + 270) = 876 sq ft
Answer: D) 876 sq ft
29. Volume of an extruded shape is area of the base, here the front, times the height, here 15 feet.
Volume = 168 * 15 = 2520 cubic ft
Answer: D) 2520 cubic ft
Answer:
It's non-proportional
Step-by-step explanation:
You could tell every 1/4 mile is 6 minutes, so every other number should be a multiple of 6 if it is a multiple of 1/4. 27 is not a multiple of 6.
-3/4 because it goes down three and over 4 by the time it hits the next readable point on the graph
Answer:
8:6
32:24
20:15
hope this helps
mark 5 stars and brainlliest please.
Step-by-step explanation:
Answer:
The probability that Aaron goes to the gym on exactly one of the two days is 0.74
Step-by-step explanation:
Let P(Aaron goes to the gym on exactly one of the two days) be the probability that Aaron goes to the gym on exactly one of the two days.
Then
P(Aaron goes to the gym on exactly one of the two days) =
P(Aaron goes to the gym on Saturday and doesn't go on Sunday) +
P(Aaron doesn't go to the gym on Saturday and goes on Sunday)
- If Aaron goes to the gym on Saturday the probability that he goes on Sunday is 0.3. Then If Aaron goes to the gym on Saturday the probability that he does not go on Sunday is 1-0.3 =0.7
- Since the probability that Aaron goes to the gym on Saturday is 0.8,
P(Aaron goes to the gym on Saturday and doesn't go on Sunday) =
P(the probability that Aaron goes to the gym on Saturday)×P(If Aaron goes to the gym on Saturday the probability that he does not go on Sunday)
=0.8×0.7=0.56
- The probability that Aaron doesn't go to the gym on Saturday is 1-0.8=0.2
- And if Aaron does not go to the gym on Saturday the probability he goes on Sunday is 0.9.
Thus, P(Aaron doesn't go to the gym on Saturday and goes on Sunday) = P(The probability that Aaron doesn't go to the gym on Saturday)×P(if Aaron does not go to the gym on Saturday the probability he goes on Sunday)
=0.2×0.9=0.18
Then
P(Aaron goes to the gym on exactly one of the two days) =0.56 + 0.18 =0.74