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stepan [7]
4 years ago
9

Two angels are complementary. One angle is 18 degrees more than 2 times the other. Find the angles.

Mathematics
1 answer:
Ludmilka [50]4 years ago
6 0
Two complementary angles = 90°
X = 18+ 2y
X + y = 90
Plug first equation into second
18 + 2y +y = 90
18 + 3y = 90
18 – 18 +3y = 90 – 18
3 y = 72
3y/3 = 72/3
Y = 24
Plug y into 2nd formula
X + 24 = 90
X + 24 -24 = 90 – 24
X = 66
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I need help with this please!!
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(-6,0)

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put y=0

-3x-18=0

or,3x=-18

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5 0
3 years ago
Can someone help me please it’s urgent
laila [671]

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7 0
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What is "the sum of twice a number and six is the same as three subtracted from the number itself"?
inysia [295]

Answer:

x=-1

Step-by-step explanation:

2x+6=3-x

Step 1: Simplify both sides of the equation.

2x+6=3−x

2x+6=3+(−x)

2x+6=−x+3

Step 2: Add x to both sides.

2x+6+x=−x+3+x

3x+6=3

Step 3: Subtract 6 from both sides.

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Step 4: Divide both sides by 3.

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Answer:

x=−1

4 0
3 years ago
Why is 2 + (−3) equal to −1? (1 point)
KiRa [710]
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5 0
3 years ago
Read 2 more answers
In △ABC, m∠A=19°, a=13, and b=14. Find c to the nearest tenth.
34kurt
We know that
Applying the law of sines

step 1
Find the value of angle B
a=13
b=14
A=19°
so

 \frac{a}{sin A} = \frac{b}{sin B} \\ a*sin B=b*sin A \\ sin B= \frac{b}{a}*sin A \\ sin B= \frac{14}{13} *sin 19 \\ sin B=0.3506 \\ B=arc sin(0.3506) \\ B=20.5°

step 2
with angle A and angle B find the angle C
A+B+C=180-----> solve for C
C=180-(A+B)------> C=180-(19+20.5)-----> C=140.5°

step 3
\frac{a}{sin A} = \frac{c}{sin C} \\ a*sin C=c*sin A \\ c=a* \frac{sin C}{sin A}  \\ c=13* \frac{sin 140.5}{sin 19}  \\ c=25.4

the answer is
the value of c is 25.4



3 0
3 years ago
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