Answer:
2/10 because if the two fraction
Answer:
Wages expense Dr ($900 × 3 days) $2,700
To wages payable $2,700
(being wages expense is recorded)
Step-by-step explanation:
The adjusting entry is as follows
Wages expense Dr ($900 × 3 days) $2,700
To wages payable $2,700
(being wages expense is recorded)
Here the wages expense is debited as it increased the expense and credited the wages payable as it also increased the liability
Since on Jan 26, it is friday so the remaining days would be 3
Answer:
The first one is
Step-by-step explanation:
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
Speed = distance / time
Speed = 120 / 33
Speed = 3.64 miles per hour
