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Goryan [66]
3 years ago
6

Triangle ABC has vertices A(4,8) B(-3,2) and C(-1,6). Triangle ABC is dilated so that the new vertices are A'(12,24) B'(-9,6) an

d C'(-3,18). What is the scale factor?
Mathematics
1 answer:
Sav [38]3 years ago
5 0
Your scale factor is 3
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Answer:

Step-by-step explanation:

Solution by substitution method

3x-4y=8

and 18x-5y=10

Suppose,

3x-4y=8→(1)

and 18x-5y=10→(2)

Taking equation (1), we have

3x-4y=8

⇒3x=4y+8

⇒x=( 4y+8)/ 3  →(3)

Putting x= (4y+8 )/3  in equation (2), we get

18x-5y=10

18( (4y+8) /3)  -5y=10

⇒24y+48-5y=10

⇒19y+48=10

⇒19y=10-48

⇒19y= -38

⇒y=- 38 /19

 ⇒y= -2→(4)

Now, Putting y=-2 in equation (3), we get

x=4y+8

x= (4(-2)+8) /3

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 ⇒x= 0/ 3

 

⇒x=0

∴x=0  and  y= -2

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Step-by-step explanation:

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Could anybody please help me on this one? I'm really stuck on this. 
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