1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Goryan [66]
2 years ago
6

Triangle ABC has vertices A(4,8) B(-3,2) and C(-1,6). Triangle ABC is dilated so that the new vertices are A'(12,24) B'(-9,6) an

d C'(-3,18). What is the scale factor?
Mathematics
1 answer:
Sav [38]2 years ago
5 0
Your scale factor is 3
You might be interested in
QUICKKKKKKKK
zavuch27 [327]
See attached picture of graph

6 0
2 years ago
If cos(2/3x+20)°=sin(2x−10)°, find the acute angles of the corresponding right triangle.
adell [148]

Answer:

A = 40°

B = 50°

Step-by-step explanation:

If cos A = sin B, then A + B = 90

So, 2x/3 + 20  + 2x - 10 = 90

      2x + 60 + 6x - 30 = 270

               8x + 30 = 270

                       8x = 240

                          x = 30

2x/3 + 20 = 60/3 + 20 = 20 + 20 = 40

2x - 10 = 2(30) - 10 = 60 - 10 = 50  or  90 - 40 = 50

       

7 0
3 years ago
Does the point given below occur on the line shown. Can you show the work please
Aneli [31]
No it doesn't. 2*0.5 + 5*0 = 1, not 19
5 0
3 years ago
How do i do this???????
Fittoniya [83]

Answer:

2y-4-6y-12=4

-4y=20

y= -5

Step-by-step explanation:

because (y+2)(y-2)=y^2-4

so we have the step to let the every part have the same denominator y^2-4

2(y-2)/(y+2)(y-2)  -6(y+2)/(y-2)(y+2)=4/(y-2)(y+2)

the denominators are the same so the equality .we just need the part over be the same 2y-4-6y-12=4

y= -5

3 0
2 years ago
Suppose you have a right triangle area marked in the ground with a base (8-h) meters long and a height h meters long. the hypote
Aleks [24]

Answer:

5.415m and 2.585m long

Step-by-step explanation:

For a right triangle

hyp^2 = opp^2 + adj^2 (Pythagoras theorem)

Given

hypotenuse = 6m

height(opposite) = h meters

Adjacent = (8-h)m

Substitute into the expression above;

6² = h²+(8-h)²

36 = h²+64-16h+h²

36 = 2h²-16h+64

2h²-16h+64-36 = 0

2h²-16h+28= 0

Divide through by 2

h²-8h+14 = 0

Using the general formula

h = 8±√8²-4(14)/2

h = 8±√64-56/2

h = 8±√8/2

h = 8±2.83/2

h = 8+2.83/2 and 8-2.83/2

h = 10.83/2 and 5.17/2

h = 5.415 and 2.585

hence the length of the height of the right triangle are 5.415m and 2.585m long

7 0
2 years ago
Other questions:
  • Sara tried to evaluate 21 : 7 x 8 step-by-step
    7·1 answer
  • Please solve the underlined question thank you!
    12·2 answers
  • Find the product. simplify if possible. -1/3 times (8 1/7)
    15·2 answers
  • Can I have some topical past paper questions on the olevel syllabus of cambridge? The code is 4024.​
    7·1 answer
  • X + y = -2<br> -x + y = 6<br> Solve the linear system
    7·1 answer
  • In the formula C = 2.1, C stands for
    7·1 answer
  • Help me out please an thank you
    10·2 answers
  • What is the value of l-12l
    8·1 answer
  • <img src="https://tex.z-dn.net/?f=9x%5E%7B2%7D" id="TexFormula1" title="9x^{2}" alt="9x^{2}" align="absmiddle" class="latex-form
    12·2 answers
  • How many solutions?
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!