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3 years ago

6

Triangle ABC has vertices A(4,8) B(-3,2) and C(-1,6). Triangle ABC is dilated so that the new vertices are A'(12,24) B'(-9,6) an

d C'(-3,18). What is the scale factor?

1 answer:

Sav [38]3 years ago

5 0

Your scale factor is 3

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If x+12 is a factor of a polynomial, what would it tell you about the polynomial

telo118 [61]

Answer:

That is has root -12 meaning if you replace x with -12 you get 0.

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Read 2 more answers

Cos 4θ − cos 2θ = sin θ

hichkok12 [17]

$cos(4\theta) - cos(2\theta) = sin(\theta)$
$-2sin(\frac{4\theta + 2\theta}{2})sin(\frac{4\theta - 2\theta}{2}) = sin(\theta)$
$-2sin(\frac{6\theta}{2}sin\frac{2\theta}{2}) = sin(\theta)$
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$\frac{-2sin(3\theta)sin(\theta)}{-2sin(\theta)} = \frac{sin(\theta)}{-2sin(\theta)}$
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3 years ago

The sector of a circle with a 60 millimeters radius has a central angle measure of 30° . What is the exact area of the sector in

ASHA 777 [7]

R = 60
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3 years ago

What is the simplified form of StartRoot StartFraction 72 x Superscript 16 Baseline Over 50 x Superscript 36 Baseline EndFractio

aalyn [17]

Answer:

StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction

Step-by-step explanation:

Apparently you want to simplify ...

$\sqrt{\dfrac{72x^{16}}{50x^{36}}}$

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

1/a^b = a^-b

(a^b)^c = a^(bc)

__

So the expression simplifies as ...

$\sqrt{\dfrac{72x^{16}}{50x^{36}}}=\sqrt{\dfrac{36}{25x^{36-16}}}=\sqrt{\dfrac{36}{25x^{20}}}\\\\\sqrt{\left(\dfrac{6}{5x^{10}}\right)^2}=\boxed{\dfrac{6}{5x^{10}}}$

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3 years ago

Calculate the distance between the points Q = (2, -1) and K = (6,-9) in the coordinate plane.

White raven [17]

Answer:

Sqrt 80 = 8.94

Step-by-step explanation:

d = sqrt[(x-x)^2 + (y-y)^2]

d = sqrt [(6-2)^2 + (-9 - - 1)^2]

d = sqrt [(4)^2 + (-8)^2]

d = sqrt (16 + 64)

d = sqrt 80

d = 4 sqrt 5 = 8.94

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3 years ago