Hello!!
The answer would be: x=6; midsegment AB= 8; midsegment RS= 16
which would also look like- x=6;AB=8;RS=16
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Answer:
a. 2/5
b. 1/2
c. 100/9
Step-by-step explanation:
a: Multiply bottom and top by 100 to keep values the same and make the fraction a whole fraction:
.12 × 100 = 12
.3 × 100 = 30
Simplify: 12/30 = 2/5
b: Multiply bottom and top by 1,000 to keep values the same and make the fraction a whole fraction:
.125 × 1,000 = 125
.25 × 1,000 = 250
Simplify: 125/250 = 1/2
c: Multiply bottom and top by 100 to keep values the same and make the fraction a whole fraction:
4 × 100 = 400
.36 × 100 = 36
Simplify: 400/36 = 100/9
The answer to the question is 1550
Answer: Graph D will be correct graph for the given function.
Explanation:
Given function
Since it is a bi-quadratic equation thus it must have 4 roots and (0,1) is one of its point.
Moreover, the degree of the function is even thus the end behavior of the function is, as and as
In graph A, function has four root but it does not have the end behavior same as function f(x).( because in this graph , as and , as .) so, it can not be the graph of given function.
In graph B, neither it has four root nor it has the end behavior same as function f(x).(because in this graph as and as .) so, it can not be the graph of given function.
In graph C, neither it has four root nor it has the same end behavior as function f(x).(because in this graph as and as.) so, it also can not be the graph of given function.
In graph D it has four root as well as it has the same end behavior as the given function. Also it passes through the point (0,1).
Thus, graph D is the graph of given function.
The area of the circle is πr², ie. 144π.
The volume of the cilinder is 12×144π = 1728π cm³.
I vote for answer A.