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lesya [120]
3 years ago
14

In a local university, 40% of the students live in dormitories. A random sample of n = 80 students is selected for a particular

study.
(a) What is the sampling distribution of P? Please provide its general shape, its standard deviation, and its mean.
(b) What is the probability that the sample proportion (the proportion living in the dormitories) is between 0.30 and 0.50?
Mathematics
1 answer:
KIM [24]3 years ago
8 0

Answer:

a) p is normally distributed with mean P = 0.4 and standard deviation

δ = 0.05477

b) P( 0.3 < p < 0.5) = 0.9312

Step-by-step explanation:

a) What is the sampling distributión of P?

   

    p(sample proportion) is normally distributed with mean P and standard  

    deviation δ = \sqrt{\frac{P(1-P)}{n} }

   

    how P = 0.40  population proportion of the students live in dormitories,        

    then p is normally distributed with mean P = 0.4 and standard deviation

     δ = \sqrt{\frac{0.4(1-0.4}{80} }

     δ = 0.05477

b) P( 0.3 < p < 0.5)

    Standardizing

    z = (p - P)/δ

    z_{1} = \frac{0.3-0.4}{0.05477}

                    = -1.82

    z_{2} = \frac{0.5-0.4}{0.05477}

                    = 1.82

     P(-1.82 < z < 1.82) = P(z < 1.82) - P(z<-1.82)

                                   =0.9656 - 0.0344

     P(-1.82 < z < 1.82) =  0.9312  

 

   

   

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Answer:

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Step-by-step explanation:

(a) Male expenditure

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Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

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CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

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