Answer:
The daily rate is $33 and the per mile rate is $0.35
Step-by-step explanation:
4x + 440y = 286
3x + 190y = 165.5
We can solve this systems of equations by multiplying the second statement by
to try and eliminate the x variable.
4x + 440y = 286
-4x -
y = -220![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
y= ![\frac{196}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B196%7D%7B3%7D)
560y = 196
y = 0.35
So, the rate per mile is 0.35. Now, with this info, let's find the daily rate by plugging it into the equation.
![4x + 440\cdot0.35 = 286\\4x + 154 = 286\\4x = 132\\x = 33](https://tex.z-dn.net/?f=4x%20%2B%20440%5Ccdot0.35%20%3D%20286%5C%5C4x%20%2B%20154%20%3D%20286%5C%5C4x%20%3D%20132%5C%5Cx%20%3D%2033)
So, the daily rate is $33 and the mile rate is $0.35.
Hope this helped!
Answer:
![\displaystyle \boxed{-3x + y = 25}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cboxed%7B-3x%20%2B%20y%20%3D%2025%7D)
Step-by-step explanation:
y - 10 = 3(x + 5)
y - 10 = 3x + 15
+ 10 + 10
__________
y = 3x + 25
- 3x - 3x
________
![\displaystyle -3x + y = 25](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-3x%20%2B%20y%20%3D%2025)
I am joyous to assist you anytime.
Answer:(-6,-10)
Step-by-step explanation:
Let’s say that A is (-5,-6) and B is (-3,2). The slope of AB is (-6-2)/(-5+3)=(-8)/(-2)=4
The equation of AB is:
y-2=4(x+3)
y=4x+14
The lines intersect in:
4x+14=x-4
3x=-18
x=-6
(-6,-10)
Answer:
First one hi is nonespon bus because
Answer:
- Let p be the population at t be the number of years since 2011. Then,
![p=2000-50t](https://tex.z-dn.net/?f=p%3D2000-50t)
- The projected population of the high school in 2015=1800
- In <u>2019</u> the population be 1600 students
Step-by-step explanation:
Given: The population at Bishop High School students in 2011 =2000
Also, Every year the population decreases by 50 students which implies the rate of decrease in population is constant.
So, the function is a linear function.
Let p be the population at t be the number of years since 2011.
Then, ![p=2000-50t](https://tex.z-dn.net/?f=p%3D2000-50t)
So at t=0, p=2000
In year 2015, t=4, substitute t=4 in the above equation ,we get
![p=2000-50(4)\\\Rightarrow\ p=2000-200\\\Rightarrow\ p=1800](https://tex.z-dn.net/?f=p%3D2000-50%284%29%5C%5C%5CRightarrow%5C%20p%3D2000-200%5C%5C%5CRightarrow%5C%20p%3D1800)
Hence, the projected population of the high school in 2015=1800
Now, put p=1600 in the function , we get
![1600=2000-50t\\\Rightarrow50t=2000-1600\\\Rightarrow50t=400\\\Rightarrow\ t=\frac{400}{50}\\\Rightarrow\ t=8](https://tex.z-dn.net/?f=1600%3D2000-50t%5C%5C%5CRightarrow50t%3D2000-1600%5C%5C%5CRightarrow50t%3D400%5C%5C%5CRightarrow%5C%20t%3D%5Cfrac%7B400%7D%7B50%7D%5C%5C%5CRightarrow%5C%20t%3D8)
Now, 2011+8=2019
Hence, in <u>2019</u> the population be 1600 students