What is the equation of the line that passes through (5, 3) and (4, 5)
1 answer:
Answer:
y = - 2x + 13
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (5, 3) and (x₂, y₂ ) = (4, 5)
m = =
= - 2, thus
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (4, 5), then
5 = - 8 + c ⇒ c = 5 + 8 = 13
y = - 2x + 13 ← equation of line
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Answer:
2x + 3y = -6
-4x + 3y = 12
5x + 3y = }
x - y = 5
Step-by-step explanation:
Standard Form is .
2x + 3y = -6, -4x +3y = 12, 5x + 3y = '?', and x - y = 5 are the equations that are in standard form.
'2x+3 = 6' does not have the 'y' to make it standard form.
'y = 2x + 5' is slope-intercept form.
There is only one change of sign, so there is only one possible positive root.
There are five changes of signs, so there are 5,3 or 1 possible negative roots.
The number of complex roots can be equal to 4,2 or 0 (degree of a polynomial - possible positive roots - possible negative roots)