Answer:
The bottle of perfume A contains more glass
Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four triangular faces
step 1
Find the surface area of Perfume A
![SA=3^{2} +4[\frac{1}{2}(3)(2.5)]=24\ in^{2}](https://tex.z-dn.net/?f=SA%3D3%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%283%29%282.5%29%5D%3D24%5C%20in%5E%7B2%7D)
step 2
Find the surface area of Perfume B
![SA=2.5^{2} +4[\frac{1}{2}(2.5)(3)]=21.25\ in^{2}](https://tex.z-dn.net/?f=SA%3D2.5%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%282.5%29%283%29%5D%3D21.25%5C%20in%5E%7B2%7D)
step 3
Compare the surface areas

therefore
The bottle of perfume A contains more glass
Answer:
c
Step-by-step explanation:
Answer:
n = - 12
Step-by-step explanation:
n/9 + 2/3 = - 2/3
n/9 = - 2/3 - 2/3
n/9 = - 4/3
n = 9(- 4/3)
n = -36/3
n = - 12
Total discount for 10 group tickets = 10 · 0.05t
Amount of discount per ticket = 0.05t
Number of tickets = 10
Cost of buying 10 single tickets = 10t
Solution:
Cost for single ticket = t dollars
Discount percent per ticket = 5%
Number of tickets bought = 10
Total discount for 10 group tickets = Number of tickets × Discount amount
= 10 × 0.05t
Total discount for 10 group tickets = 10 · 0.05t
Amount of discount per ticket = 5%t
=
t
= 0.05t
Amount of discount per ticket = 0.05t
Number of tickets = 10
Cost of buying 10 single tickets = 10t