A. Y=1/2x + 2
Hope this helps :))
<span>we have that
the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]
we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]
z1=3[cos 110° + i sin 110°]
cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]
z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is
</span>z1=3[cos 110° + i sin 110°]<span>
</span>z2=3[cos 230° + i sin 230°]
z3=3[cos 350° + i sin 350°]<span>
</span>
The correct answer is B
<h2><u>EXPLANATION</u></h2>
The commutative property of multiplication says that, if you are multiplying two numbers, the order of the multiplication does not matter. You will get the same result, no matter which one you bring first or second during the multiplication process.
That is, if <em>a </em>and <em>b</em> are two real numbers, then the commutative property of multiplication says that,
![a\times b = b\times a](https://tex.z-dn.net/?f=a%5Ctimes%20b%20%3D%20b%5Ctimes%20a)
So for the above options,
![6\times 4 = 4\times 6](https://tex.z-dn.net/?f=6%5Ctimes%204%20%3D%204%5Ctimes%206)
![24= 24](https://tex.z-dn.net/?f=24%3D%2024)
<em>Note that the numbers have not changed, so their values will not change also. </em>
We are NOT referring to a situation where the numbers will change whilst their values is still the same.
Say the apprentice earns x dollars an hour, and the plumber earns x+15 dollars per hour. Write the equation:
40(x+x+15)=2200
Dividing by 40, we see that:
2x+15=55
Subtracting 15, we see that 2x=40, so x=20. As a result, the apprentice earns $20 an hour, and the plumber earns #35 per hour.